Answer:
A
Step-by-step explanation:
expanding the bracket, we would have
-2x -18 = -x+1+2
-2x+x= 3 +18
-x=21
x=-21
if its diameter is 34, then its radius is half that or 17.
![\textit{surface area of a sphere}\\\\ SA=4\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=17 \end{cases}\implies \begin{array}{llll} SA=4\pi (17)^2\implies SA=1156\pi \\\\\\ SA\approx 3631.68~m^2 \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Bsurface%20area%20of%20a%20sphere%7D%5C%5C%5C%5C%20SA%3D4%5Cpi%20r%5E2%20~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D17%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20SA%3D4%5Cpi%20%2817%29%5E2%5Cimplies%20SA%3D1156%5Cpi%20%5C%5C%5C%5C%5C%5C%20SA%5Capprox%203631.68~m%5E2%20%5Cend%7Barray%7D)
Answer:
The answer is x = 8.
Step-by-step explanation:
Answer:
negative line
Step-by-step explanation:
Answer:

Step-by-step explanation:
ΔDAC and ΔDCB are similar (AA). Therefore the sides are in proportion:

We have DA = 3cm and DB = 8 cm. Substitute:
<em>cross multiply</em>


