Write a translation rule that maps point d(7 -3) onto point d'(2 5)

tatuchka [14]

Answer:

y= 10 - 1/4x (FOR LIN)

y=20 - 2/3x ( FOR DIEGO)

Y is what you want , 10 or 20 is what you start with .. whatever amount they drink per second you put in front of x which is the amount of seconds .

6 0

2 years ago

A group of campers is going to occupy 6 campsites at a campground. There are 16 campsites from which to choose. In how many ways

Pachacha [2.7K]

Answer:

The campsites can be chosen in 5,765,760 different ways.

Step-by-step explanation:

Given that a group of campers is going to occupy 6 campsites at a campground, and there are 16 campsites from which to choose, to determine in how many ways the campsites can be chosen, the following calculation must be performed:

16 x 15 x 14 x 13 x 12 x 11 = X

240 x 182 x 132 = X

240 x 24,024 = X

5,765,760 = X

Therefore, the campsites can be chosen in 5,765,760 different ways.

8 0

2 years ago

A marketing research company needs to estimate the average total compensation of CEOs in the service industry. Data were randoml

mezya [45]

SOLUTION:

Step 1 :

In this question, we are told that a marketing research company needs to estimate the average total compensation of CEOs in the service industry.

We also have that: Data were randomly collected from 38 CEOs and the 98% confidence interval was calculated to be ($2,181,260, $5,836,180).

Then, we are asked to find the margin error for the confidence interval.

Step 2:

We need to recall that:

$\text{Higher Confidence Interval, CI}_{H\text{ = }}X\text{ + }\frac{Z\sigma}{\sqrt[]{n}}$ $\text{Lower Confidence Interval , CI}_{L\text{ }}=\text{ X - }\frac{Z\sigma}{\sqrt[]{n}}$

It means that:

$\vec{}X\text{ = }\frac{CI_{H\text{ }}+CI_L}{2}$ $\text{Margin of error, }\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{CI_{H\text{ - }}CI_L}{2}$

where,

$CI_H\text{ = }$$5,836,180$\text{ }$$$$ $CI_{L\text{ }}=\text{ }2,181,260$

putting the values into the equation for the margin of error, we have that:

$\text{Margin of error,}\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{5,836,180\text{ - }2,181,260\text{ }}{2}$ $\begin{gathered} =\text{ }\frac{3654920}{2} \\ =1,\text{ 827, 460} \end{gathered}$

CONCLUSION:

The margin error for the confidence interval is 1, 827, 460

5 0

4 months ago

Find the equality represented by the graph?

Talja [164]

Answer:

$-x+4y$