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Aliun [14]
3 years ago
12

PLEASE ANSWER!!!

Mathematics
1 answer:
Alexandra [31]3 years ago
7 0
<span>2% of 50 → 2 per cent of 50 = 0.02 × 50 = 1 → 1 book .... so Alexa Read 51 books

</span>
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How do I solve this question I’ve been stuck on this since last night
meriva

Observation one

From the markings on the diagram <1 = 60o The left triangle is at least isosceles. Therefore equal sides produce equal angles opposite them.

Now we have accounted for 2 angles that are equal (each is 60 degrees) and add up to 120 degrees. The third angle (angle 2) is found from this equation.

<1 + 60 + <2 = 180 degrees.  All triangles have 180 degrees.

60 + 60 + <2 = 180

Observation 2

<2 = 60 degrees.

120 + <2 = 180

m<2 = 180 - 120

m<2 = 60 degrees.

Observation 3

m<3 = 120

<2 and <3 are supplementary.

Any 2 angles on the same straight line are supplementary

60 + <3 = 180

<3 = 180 - 60

<3 = 120

Observation 4

m<4 = 40 degrees.

All triangles have 180 degrees. No exceptions.

m<4 + 20 +m<3 = 180

m<4 + 20 + 120 = 180

m<4 + 140 = 180          

m<4 = 180 - 140

m<4 = 40


8 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
2 years ago
What is a fraction strips
MrRa [10]

Fraction strips are rectangular pieces (electronic or copied on paper strips) to represent different parts of the same whole. They can be cut apart and manipulated to see how various parts can be added together to make the whole or compare different fractional amounts for equivalency

6 0
3 years ago
Read 2 more answers
1) After striking a pair of arcs from each endpoint of a line segment, what is the next step in constructing the segment's perpe
qaws [65]
After striking a pair of arcs from each endpoint of a line segment, just join the intersection point of the 1st pair (above the segment) with the intersection point
of the 2nd pair (under the segment)
And this is how you construct the segment's perpendicular bisector


6 0
3 years ago
Read 2 more answers
The icon indicates an exercise designed to provide practice using a calculator. solve y-6= -14
Anastaziya [24]
Y-6=-14
+6 +6
y=-8
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6 0
3 years ago
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