About 7.1 litres all you have to do is to divide divide the volume value by 1000
Answer:
0.00125 moles H₃X
Solution and Explanation:
In this question we are required to calculate the number of moles of triprotic acid neutralized in the titration.
Volume of NaOH used = final burette reading - initial burette reading
= 39.18 ml - 3.19 ml
= 35.99 ml or 0.03599 L
Step 1: Moles of NaOH used
Number of moles = Molarity × Volume
Molarity of NaOH = 0.1041 M
Moles of NaOH = 0.1041 M × 0.03599 L
= 0.00375 mole
Step 2: Balanced equation for the reaction between triprotic acid and NaOH
The balanced equation is;
H₃X(aq) + 3NaOH(aq) → Na₃X(aq) + 3H₂O(l)
Step 3: Moles of the triprotic acid (H₃X used
From the balanced equation;
1 mole of the triprotic acid reacts with 3 moles of NaOH
Therefore; the mole ratio of H₃X to NaOH is 1 : 3.
Therefore;
Moles of Triprotic acid = 0.00375 mole ÷ 3
= 0.00125 moles
Hence, moles of triprotic acid neutralized during the titration is 0.00125 moles.
Answer:
It is greater than -600kJ/mol and the amount of energy required to break bonds is greater than the amount of energy released in forming bonds.
Explanation:
In an endothermic reaction, the reaction requires a determined amount of energy to occurs.
The reaction of the problem has H = -600kJ/mol. The reaction is endothermic and the energy that the reaction needs is absorbed by the reactants. That means, the energy of products:
Is greater than -600kJ/mol and the amount of energy required to break bonds is greater than the amount of energy released in forming bonds.
Answer:
The answer to your question is below
Explanation:
1) 0.143g of Mg into atoms
- Look for the atomic number of Magnesium in the Periodic table
Atomic number = 24.31 g
-Use the Avogadro's number to find the number of atoms
24.31g ------------------- 6.023 x 10²³ atoms
0.143 g ----------------- x
x = (0.143 x 6.023 x 10²³) / 24.31
x = 8.613 x 10²² / 24.31
x = 3.54 x 10²¹ atoms
2) 0.101 kg of Ti into atoms
-Look for the atomic number of Titanium in the Periodic table
Atomic number = 47.87 g
-Use the Avogadro's number to find the number of atoms
47.87 g --------------------- 6.023 x 10²³
101 g ---------------------- x
x = (101 x 6.023 x 10²³) / 47.87
x = 6.08x 10²⁵ / 47.87
x = 1.27 x 10²⁴ atoms
It is a devoid of matter and gaseous pressure and atmospheric pressure.
