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olga2289 [7]
3 years ago
6

Why do we balance chemichal reactions

Chemistry
2 answers:
Delvig [45]3 years ago
6 0

Answer:

We balance chemical equations due to the law of conservation of mass, which states that mass can neither be created or destroyed. Therefore, in a chemical reaction, the total mass of the reactants must be equal to the total mass of the products. Balancing equations accounts for the total mass of the reactants and the total mass of the products.

Explanation:

We balance chemical equations due to the law of conservation of mass, which states that mass can neither be created or destroyed. Therefore, in a chemical reaction, the total mass of the reactants must be equal to the total mass of the products. Balancing equations accounts for the total mass of the reactants and the total mass of the products.

weeeeeb [17]3 years ago
3 0

Answer:

to satisfy the law of conservation of matter.

the law of conservation states that matter can not be created nor destroyed.

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How many molecules of sulfur trioxide are in 78.0 grams?
Zarrin [17]
Molecular formula of sulfur trioxide is SO₃
Molar mass of SO₃ is -  32 + (16 x 3 ) = 80 g/mol
1 mol of any substance consists of 6.022 x 10²³ units. In 1 mol of SO₃ there are 6.022 x 10²³ molecules of SO₃
in 80 g of SO₃ - there are 6.022 x 10²³ molecules of SO₃
Therefore in 78 g of SO₃ - there are 6.022 x 10²³ /80 x 78 = 5.871 x 10²³ SO₃ molecules
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4 years ago
Why dont we include the mass of an atoms electrons in the atomic mass?
Oxana [17]
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3 years ago
Compare a heterogeneous mixture and a homogeneous mixture
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3 years ago
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3 years ago
When a cube of manganese oxide was added to a solution of hydrogen peroxide, water and oxygen were produced. Manganese oxide was
lesya692 [45]

Answer:

Chilling the hydrogen peroxide solution  

Explanation:

The MnO₂ is acting as a catalyst.

Chilling the hydrogen peroxide solution reduces the average kinetic energy of the H₂O₂ molecules.

Fewer of them will have enough kinetic energy to overcome the activation energy of the reaction. The rate will decrease.

A is wrong. Using a larger amount of solution does not increase the number of H₂O₂ molecules that can reach the surface of the catalyst per second. There is no effect on the rate.

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