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marishachu [46]
4 years ago
12

Draw one of the stereoisomers of the product formed when benzaldehyde (c6h5cho) is treated with ph3p═chcooch3.

Chemistry
1 answer:
8_murik_8 [283]4 years ago
8 0
This reaction is known as Wittig Reaction. A powerful reaction for the synthesis of Alkene. In question the starting materials are aldehyde and a Phosphorous Ylide. Ylide when reacted with aldehyde produces a four membered ring which on rearrangement gives Alkene and triphenylphosphine oxide. Phosphorous having great affinity toward the oxygen is the driving force of this rearrangement. The reaction along with product (highlighted blue) is as follow,

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What is the pH of a substance with a hydrogen concentration of 1.0 x 10-13?
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Answer:

Favorite Answer

1.0 x10^-14 = (1.0 x 10^-13) (x)

x = 1.0 x 10^-1 = 0.1 M (this is the [OH-])

pOH = -log 0.1 = 1.0

Explanation:

I hope this helps :) sorry if not :(

4 0
3 years ago
Draw the structure for the ring compounds with formulas C6H12 and C6H6
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8 0
3 years ago
If 15.0 mL of phosphoric acid completely neutralizes 38.5 mL of 0.150 mol/L calcium hydroxide, what is the concentration of the
Sedbober [7]

Answer:

Let me give it a try.

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + H2O

Balancing this reaction

2H3PO4 + 3Ca(OH)2 == Ca3(PO4)2 + 6H2O.

Moles= Molarity x Volume

Volume = 38.5ml = 0.0385L

Moles of Ca hydroxide = 0.150m/L x 0.0385L

(Notice the units canceling out...leaving moles).

=0.005775moles of Ca(OH)2.

From balanced reaction...

3moles of Ca(OH)2 completely reacts with 2moles of H3PO4

0.005775moles of Ca(OH)2 would completely react with....

= 0.005775 x 2/(3)

=0.00385moles of H3PO4.

Now we're looking for its Concentration in Mol/L

Molarity=Moles of solute/Volume of solution(in L)

Volume of solution assuming no other additions to the reaction = 15ml + 38.5ml =53.5ml =0.0535L

Molarity = 0.00385/0.0535

=0.072Mol/L.

If this is wrong

then Simply Try The formula for Mixing of solutions

C1V1 = C2V2

0.15 x 38.5 = C2 x (15+38.5)

C2 = 0.11M/L.

7 0
3 years ago
Estimate the pH of the resulting solution if you mixed equal amounts of hydrochloric acid (HCI) and sodium hydroxide (NaOH).
ioda
It obtains a neutral pH (7). The combination of a strong acid and a strong base results in a neutral pH. The pH of HCl is about 1, and the pH of NaOH is 14.
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3 years ago
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