Algebraically find three consecutive positive integers such that the square of the first is equal to the third.
1 answer:
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<em>Note: You may have missed to add the dot plots chart, so I found the chart after a little research and hence, I am attaching it and based on that dot plot chart I am solving the question which anyways would clear you concept.</em>
Answer:
''The median for the students is 2 and the median for the teachers is 3'' is the right option which compares the medians of the data.
Step-by-step explanation:
Data for students from the dot plot in order
Calculating Median for students:
0, 0, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4
As you can see, we do not have just one middle number but we have a pair of middle numbers i.e. 2 and 2, so the median is the average of these two numbers:
Median = (2+2)/2
=4/2
= 2
Data for teachers from the dot plot in order
Calculating Median for teachers:
0, 1, 1, 1, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 6, 8
As you can see, we do not have just one middle number but we have a pair of middle numbers i.e. 3 and 3, so the median is the average of these two numbers:
Median = (3+3)/2
=6/2
= 3
Therefore, ''the median for the students is 2 and the median for the teachers is 3'' is the right option which compares the medians of the data.
