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4 years ago

Physical science!!! please help

Chemistry

1 answer:

IgorLugansk [536]4 years ago

7 0

Answer:

The correct answer is : No, because there are 4 hydrogen atoms on the reactants side and 2 on the products side.

Explanation:

$NH_4NO_3\rightarrow N_2O+H_2O$

The given reaction equation is not balanced because:

Number of hydrogen atoms on both sides are not equal that is 4 on reactants side and 2 on products side.
Number of oxygen atoms on both sides are not equal that is 3 on reactants side and 2 on products side.

In a balanced chemical equation number of atoms of each elements are equal on both sides.

So, the balanced chemical equation will be:

$NH_4NO_3\rightarrow N_2O+2H_2O$

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The value of ΔH for the reaction below is -72 kJ. __________ kJ of heat are released when 1.0 mol of HBr is formed in this react

eimsori [14]

Answer:

36 KJ of heat are released when 1.0 mole of HBr is formed.

Explanation:

By Hess law,

The heat of any reaction ΔH for a specific reaction is equal to the sum of the heats of reaction for any set of reactions which in sum are equivalent to the overall reaction:

H 2 (g) + Br 2 (g) → 2HBr (g) ΔH = -72 KJ

This is the energy released when 2 moles of HBr is formed from one mole each of H2 and Br2.

Therefore, Heat released for the formation of 1 mol HBr would be half of this.

Hence,

ΔHreq = -36 kJ

36 KJ of heat are released when 1.0 mole of HBr is formed.

4 0

3 years ago

Identify the term that matches each electrochemistry definition.

anygoal [31]

Answer: a. Cathode

b. Galvanic cell

c. Anode

d. Electrolytic cell

e. half reaction

Explanation:

Galvanic cell or Electrochemical cell is defined as a device which is used for the conversion of the chemical energy produced in a spontaneous redox reaction into the electrical energy.

Electrolytic cell is a device where electrical energy is used to drive a non spontaneous chemical reaction.

In the electrochemical cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode. Thus the electrons are produced at anode and travel towards cathode.

The balanced two-half reactions will be:

Oxidation half reaction : $M\rightarrow M^{n+}+ne^-$

Reduction half reaction : $N^{n+}+ne^-\rightarrow N$

Thus the overall reaction will be: $M+N^{n+}\rghtarrow M^{n+}+N$

4 0

3 years ago

A chemist makes of nickel(II) chloride working solution by adding distilled water to of a stock solution of nickel(II) chloride

Lady_Fox [76]

Answer:

0.0900 mol/L

Explanation:

A chemist makes 330. mL of nickel(II) chloride working solution by adding distilled water to 220. mL of a 0.135 mol/L stock solution of nickel(II) chloride in water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits.

Step 1: Given data

Initial concentration (C₁): 0.135 mol/L

Initial volume (V₁): 220. mL

Final concentration (C₂): ?

Final volume (V₂): 330. mL

Step 2: Calculate the concentration of the final solution

We prepare a dilute solution from a concentrated one. We can calculate the concentration of the working solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 0.135 mol/L × 220. mL/330. mL = 0.0900 mol/L

3 0

3 years ago

A. Convert the following Fahrenheit temperatures to Celsius (you may use a calculator):

Bezzdna [24]

37C
20C
-6.67C
50F
86F
-40F

4 0

3 years ago

Tellurium has eight isotopes: Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), T

Elena-2011 [213]

The average atomic mass of tellurium, calculated from its eight isotopes (Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), Te-128 (31.79%), and Te-130 (34.48%)) is 127.723 amu.

The average atomic mass of Te can be calculated as follows:

$A = m_{Te-120}\%_{Te-120} + m_{Te-122}\%_{Te-122} + m_{Te-123}\%_{Te-123} + m_{Te-124}\%_{Te-124} + m_{Te-125}\%_{Te-125} + m_{Te-126}\%_{Te-126} + m_{Te-128}\%_{Te-128} + m_{Te-130}\%_{Te-130}$

Where:

m: is the mass

%: is the abundance percent

Knowing all the masses and abundance values, we have:

$A = 120*0.09\% + 122*2.46\% + 123*0.87\% + 124*4.61\% + 125*6.99\% + 126*18.71\% + 128*31.79\% + 130*34.48\%$

To find the average atomic mass we need to change all the percent values to decimal ones

$A = 120*9 \cdot 10^{-4} + 122*2.46 \cdot 10^{-2} + 123*8.7\cdot 10^{-3} + 124*4.61 \cdot 10^{-2} + 125*6.99\cdot 10^{-2} + 126*0.1871 + 128*0.3179 + 130*0.3448 = 127.723$

Therefore, the average atomic mass of tellurium is 127.723 amu.

You can find more about average atomic mass here brainly.com/question/11096711?referrer=searchResults

I hope it helps you!

4 0

3 years ago