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Charra [1.4K]
3 years ago
14

How many atoms are in C₆H₁₂O₆

Chemistry
2 answers:
telo118 [61]3 years ago
5 0

Answer:

1 molecule of glucose contains 6 atoms of C, 12 atoms of H, and 6 atoms of O • 1 mole of glucose contains 6 moles of C atoms, 12 moles of H atoms, and 6 moles of O atoms.

Explanation:

N76 [4]3 years ago
3 0

Answer:

There are 24 atoms in one molecule of C6 H12 06. This chemical compound has 6 atoms of carbon, 12 atoms of hydrogen, and 6 atoms of oxygen.

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The most likely outcome is that carrier protein dysfunction will increase the gradient which will lead to disruption of cellular metabolism.

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HELP ASAP!!! Which two energy transformations are shown in the photo? A. Chemical energy → electromagnetic energy B. Chemical en
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Chemical energy _ thermal energy

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What is the lightest particle in the following 1)electron 2)proton 3)neutron 4)photon
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1) Electron

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It carries a negative charge of 1.602176634 × 10−19 coulomb, which is considered the basic unit of electric charge. The rest mass of the electron is 9.1093837015 × 10−31 kg, which is only 1/1,836the mass of a proton.

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Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t
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<u>Answer:</u> The mass of decane produced is 1.743\times 10^2g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol

The chemical equation for the hydrogenation of decene follows:

C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = \frac{1}{1}\times 1.225=1.225mol of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g

Hence, the mass of decane produced is 1.743\times 10^2g

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3 years ago
What is the amount of space that a gas takes up called?
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