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ANEK [815]
3 years ago
12

Farmer brown is planting crops in his feild s. He wants to prevent the topsoil from being blown away by the wind or washed away

from by water. Which of these steps should he take. A: plow the soil many times. B: plant crops close together. C: water crops often to wet soil. D: leave the land free of crops for a long time
Chemistry
2 answers:
Ratling [72]3 years ago
4 0
Hey!

I would say the answer is A. Plow the soil many times to lessen the chance of the topsoil being blown away.

Hope this helps !
Ksivusya [100]3 years ago
4 0

Answer:

C: water crops often to wet soil.

Explanation:

Working in the plan industry, it becomes obvious that when watering the plants often, it will pack down the topsoil into the plant. Topsoil is lose at first as stated above, but when enough water gets on it, it becomes almost like mud. This is the kind of topsoil you want. No wind or water will mess it up because it already it watered! It will also help the grow. In addition, plowing is not correct because you only need to plow twice in the plant process. Before you plant the seeds, and to harvest the crops. If you plow to soon and often, you won’t have any plants.

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For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox
ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: m_{N2}=10.682 g N_2

2) Limiting reagent: NO

3) Ammount of excess reagent: m_{N2}=4.274 g

Explanation:

<u>The reaction </u>

2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)

Moles of nitrogen monoxide

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n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol

Moles of hydrogen

Molecular weight: M_{H2}=2 g/mol

n_{H2}=\frac{m_{H2}}{M_{H2}}

n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted

m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}

m_{N2}=10.682 g N_2

2) <u>Limiting reagent</u>: NO

3) <u>Ammount of excess reagent</u>:

m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}

m_{N2}=4.274 g

8 0
3 years ago
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