Given:
Endpoints of segment AB are A(- 18, 5) and B(- 4, 5).
Point Z is located exactly 1/8 of the distance from A to B.
To find:
The value of the x-coordinate of point Z.
Solution:
Point Z is located exactly 1/8 of the distance from A to B.
AZ:AB=1:8
AZ:ZB = AZ:(AB-AZ)= 1:(8-1) = 1:7
It means point Z divided segment AB in 1:7.
Using section formula, the x coordinate of point Z is
Therefore, the required x-coordinate of point Z is -16.25.
Thirty thousand nine hundred and six.
I see. Imagine you have f(x)=|x|. It's a V shaped graph.
Now if f(x)=|x|, 2f(x)=2|x|.
Graph Transformation Rule:
af(x), multiply y-coordinates by a.
*Ultimately, you'd still have a V shaped graph in 2f(x)=2|x|, but the y values of all the coordinates in f(x)=|x| would have to be multiplied by 2 giving you 2f(x)=2|x|.
Answer:
f(x) = -60 is your answer
Step-by-step explanation:
Plug in 3 for x
f(x) = 5x² - 7(4x + 3)
f(x) = 5(3²) - 7(4(3) + 3)
Follow PEMDAS. First, solve the parenthesis
3² = 9
4(3) + 3 = 12 + 3 = 15
f(x) = 5(9) - 7(15)
Multiply
f(x) = 45 - 105
Simplify. Subtract
f(x) = 45 - 105
f(x) = -60
f(x) = -60 is your answer
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