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Mashutka [201]
3 years ago
7

The sum of two consecutive odd integers is -120. find the two integers

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0
The numbers are 59 and 61
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Faces A and C are squares.
zysi [14]
Answer

Square prism

It has 2 squares and 4 rectangles
4 0
3 years ago
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POSSIBLE POINTS: 10
Nadusha1986 [10]

Answer:

5 + 3t

Step-by-step explanation:

t = amount Tanya has

Lucy = $5 more than 3x of what Tanya has

5 0
3 years ago
If the measure of angle 1 the measure of angle 2 = 180 and the measure of angle 3 the measure of angle 2 = 180 then the measure
Vitek1552 [10]
If<span> the degree </span>measure<span> of </span>two<span> complementary </span>angles<span> are in the ratio of </span>1<span>:14, ... These are similar to complementary </span>angles<span>, except </span>their<span> sum is </span>180<span> degrees. ... </span>1<span> = </span>angle 3<span>, (because they are vertical </span>angles<span>), </span>then<span> the </span>measure<span> of </span>angle 3<span> = y - 5.</span>
3 0
3 years ago
Based on the polynomial remainder theorem, what is the value of the function when x = 3?
dsp73

Answer:

64

Step-by-step explanation:

Evaluate x^4 + 3 x^3 - 6 x^2 - 12 x - 8 where x = 3:

x^4 + 3 x^3 - 6 x^2 - 12 x - 8 = 3^4 + 3×3^3 - 6×3^2 - 12×3 - 8

3^3 = 3×3^2:

3^4 + 3×3×3^2 - 6×3^2 - 12×3 - 8

3^2 = 9:

3^4 + 3×3×9 - 6×3^2 - 12×3 - 8

3×9 = 27:

3^4 + 3×27 - 6×3^2 - 12×3 - 8

3^2 = 9:

3^4 + 3×27 - 69 - 12×3 - 8

3^4 = (3^2)^2:

(3^2)^2 + 3×27 - 6×9 - 12×3 - 8

3^2 = 9:

9^2 + 3×27 - 6×9 - 12×3 - 8

9^2 = 81:

81 + 3×27 - 6×9 - 12×3 - 8

3×27 = 81:

81 + 81 - 6×9 - 12×3 - 8

-6×9 = -54:

81 + 81 + -54 - 12×3 - 8

-12×3 = -36:

81 + 81 - 54 + -36 - 8

81 + 81 - 54 - 36 - 8 = (81 + 81) - (54 + 36 + 8):

(81 + 81) - (54 + 36 + 8)

| 8 | 1

+ | 8 | 1

1 | 6 | 2:

162 - (54 + 36 + 8)

| 1 |  

| 5 | 4

| 3 | 6

+ | | 8

| 9 | 8:

162 - 98

| | 15 |  

| 0 | 5 | 12

| 1 | 6 | 2

- | | 9 | 8

| 0 | 6 | 4:

Answer:  64

5 0
3 years ago
Read 2 more answers
Choose the equation that could be used to find three consecutive integers whose sum is 75. n + (n + 1) + (n + 2) = 75 n + (n + 2
Vesna [10]
Correct Answer:
First Option

Let the first integer be n.
Since the integers are consecutive, the integer next to n will be n+1
and so the third integer will be n+2

Therefore, the three integers are:
n , n +1, n+2

Their sum is 75. So we can write the equation as:

n + (n+1) + (n+2) = 75

This equation can be used to find n. After finding n, we can find the next two integers by finding (n+1) and (n+2)

8 0
3 years ago
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