Question

Find an equation of the line having the given slope and containing the given point. m=8 (-4,-3)

Answer 1

Answer:

$y=8x+29$

Step-by-step explanation:

Since we know the slope and a point, we can use the point-slope form.

The point-slope form is:

$y-y_1=m(x-x_1)$

Substitute 8 for m, and let (-4,-3) be x₁ and y₁, respectively. Thus:

$y-(-3)=8(x-(-4))$

Simplify:

$y+3=8(x+4)$

Distribute:

$y+3=8x+32$

Subtract 3 from both sides:

$y=8x+29$

And we're done!