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3 years ago

How to do this and how to find the numbers for it?

Mathematics

1 answer:

hodyreva [135]3 years ago

5 0

So I have the formula for the reflection over the x-axis is from (x,y) to (x,-y), and the reflection for the y-axis is (-x,y). Next, I have the original for A(2,-2), B(2,-6), and (9,-6) which is reflection over x-axis which is A(2,2), B(2,6), and C(9,6). Then, I have A(-2,-2), B(-2,-6), and C(-9,-6) for the reflection over the y-axis. Hope it help!

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What are the potential solutions to the equation 2ln(x+3)=0

skad [1K]

$2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1$

Expanding the left side gives

$x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0$

which gives two solutions, $x=-4$ and $x=-2$ . But if $x=-4$ , then $\ln(x+3)=\ln(-1)$ , but this number isn't real, so $x=-4$ is an extraneous solution. Meanwhile if $x=-2$ , you get $\ln(-2+3)=\ln1=0$ , so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.

4 0

3 years ago

Read 2 more answers

Is a flame test qualitative or quantitative test for the identity of an unknown explain?

kolbaska11 [484]

The answer is;
Flame test is a qualitative test".
Flame test is performed for detecting metals in a compound and metals are detected by the color of the flame, and flame color identifies that which metal is this. so this is a qualitative test, different types of metals shows different color of flames.

6 0

3 years ago

Find each quotient. Write in simplest form. keep answer as fraction - not decimal

kirill [66]

So we are given the expression:

$\frac{mn^{2}}{4}$ ÷ $\frac{m^{2}n}{8}$

When we divide fractions, we must flip the second term and change the sign to multiplication:

$\frac{mn^{2}}{4} *\frac{8}{m^{2}n}$

And then we multiply across:

$\frac{mn^{2}}{4} *\frac{8}{m^{2}n}= \frac{8mn^{2}}{4m^{2}n}$

Then we can break apart all of the like variables for simplification:

$\frac{8mn^{2}}{4m^{2}n}=\frac{8}{4} * \frac{m}{m^{2}} *\frac{n^{2}}{n}$

When we simplify variables through division, we subtract the exponent of the numerator from the exponent of the denominator. So we then have:

$\frac{8}{4} =2$

$\frac{m}{m^{2}}=m^{-1} =\frac{1}{m}$

$\frac{n^{2}}{n}=n^{1}=\frac{n}{1}$

So then we multiply all of these simplified parts together:

$\frac{2}{1}*\frac{1}{m}*\frac{n}{1} =\frac{2n}{m}$

So now we know that the simplified form of the initial expression is: $\frac{2n}{m}$ .

3 0

3 years ago

60.April would like to invest $200 in the bank for one year. Three banks all have a nominal APR of 1.5%, but compound the intere

mojhsa [17]

Answer:

$203.02

Step-by-step explanation:

Since the bank in question compounds interest continuously, the following equation should be used to determine the final balance (B) in April's account:

$B= 200*e^{i*t}$