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netineya [11]
2 years ago
7

What are the values of the variables in the triangle below?

Mathematics
1 answer:
harkovskaia [24]2 years ago
8 0

Answer:

D) x=9 ; y=3√(3)

Step-by-step explanation:

Sin(30)=\cfrac{y}{6\sqrt{3} }

\cfrac{18y}{6\sqrt{3}}=18\sin \left(30^{\circ \:}\right)

\sqrt{3}y=9

\cfrac{\sqrt{3}y}{\sqrt{3}}=\cfrac{9}{\sqrt{3}}

y=3\sqrt{3}

~

Cos(30)=\cfrac{x}{6\sqrt{3} }

\cfrac{18x}{6\sqrt{3}}=18\cos \left(30^{\circ \:}\right)

\sqrt{3}x=9\sqrt{3}

\cfrac{\sqrt{3}x}{\sqrt{3}}=\cfrac{9\sqrt{3}}{\sqrt{3}}

x=9

Therefore, x=9 and y=3√(3)

~

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\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

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