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timofeeve [1]
3 years ago
9

Zachary is solving the following equation.

Mathematics
1 answer:
Sever21 [200]3 years ago
5 0

Don't know if there was supposed to be another option but, it would be distribute over (x - 8).

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Help ASAP Please. Working on this now. Look at picture for question and answer A, B, C​
Reika [66]

Answer:

look at step by step

Step-by-step explanation:

A) That is the number of bacteria that originally started in the culture

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You invest $2,000 in an account that is compounded annually at an interest rate of 5%. You never withdraw money from the account
Yuki888 [10]
Formula for amount for compound interest:

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None in the option look like the answer we have.

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4 years ago
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Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the
sp2606 [1]

Given:

The given quadratic polynomial is :

x^2-x-12

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

x^2-x-12

Equate the polynomial with 0 to find the zeroes.

x^2-x-12=0

Splitting the middle term, we get

x^2-4x+3x-12=0

x(x-4)+3(x-4)=0

(x+3)(x-4)=0

x=-3,4

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}

x^2-(3+(-4))x+(3)(-4)

x^2-(-1)x+(-12)

x^2+x-12

Therefore, the required polynomial is x^2+x-12.

4 0
3 years ago
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