<span>A triangle with one angle greater than 90 degrees is an obtuse triangle. There are other names for triangles that are based, at least in part, on their angles. For instance, a right triangle has one right angle, which is 90 degrees. The degrees of the other two angles add up to 90, for a total of 180 degrees.</span>
Answer: The explanation is correct.
Step-by-step explanation:
The interpretation of 95% confidence interval for population mean is that "A person can be 95% sure that the true population mean lies in it."
Given : The admissions director from Big City University found that (107.8, 116.2) is a 95% confidence interval for the mean IQ score of all freshmen.
Interpretation: The admissions director can be 95% sure that the true population mean IQ score of all freshmen lies in (107.8, 116.2).
i.e. There is a 95% probability (chance) that the interval from 107.8 to 116.2 contains μ.
Hence, the explanation is absolutely "correct" .
Answer:
First, collect the like terms
36x+34x=180+2-2
Solve,
74x=180
x=180/74
2.43243243243
When you round it, it will be approximately,
x≅2.43
Step-by-step explanation:
I hope it helped please give me brainliest
To solve for x and y, you need to know if the triangles are congruent. They are because of their congruent sides and exterior angles are the same measure.
Now you know that the triangles are congruent, you can set up a proportion for the side lengths you are looking for.
For x...
22/10=x/12. Then cross mutiply. x =26.4
You can do this because the triangles are congruent.
For y...
22/10 =37.4/y. Then you cross multiply. y=17
The correct answer is B.
Given:
A(-5,4)
B(3,4)
C(3,-5)
So point D is:
so point D is (-5,-5)
For AB is
Distance between two point is:
![\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%28x_1%2Cy_1%29and%28x_2%2Cy_2%29%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%20%5Cend%7Bgathered%7D)
so distance between A(-5,4) and B(3,4) is:
![\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%3D%5Csqrt%5B%5D%7B%283-%28-5%29%29%5E2%2B%284-4%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B%288%29%5E2%2B0%5E2%7D%20%5C%5C%20%3D8%20%5Cend%7Bgathered%7D)
So AB is 8 unit apart.
For B(3,4) and C(3,-5).
![\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%3D%5Csqrt%5B%5D%7B%283-3%29%5E2%2B%28-5-4%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B0%5E2%2B%28-9%29%5E2%7D%20%5C%5C%20%3D9%20%5Cend%7Bgathered%7D)
So BC is 9 unit apart.
For fourth bush point is (-5,-5) it left of point C(3,-5) is:
![\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%3D%5Csqrt%5B%5D%7B%283-%28-5%29%29%5E2%2B%28-5-%28-5%29%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B%288%29%5E2%2B0%5E2%7D%20%5C%5C%20%3D8%20%5Cend%7Bgathered%7D)
so fourth bush is 8 unit left of C.
For fourth bush(-5,-5) below to point A(-5,4)
![\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%3D%5Csqrt%5B%5D%7B%28-5-%28-5%29%29%5E2%2B%284-%28-5%29%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B0%5E2%2B9%5E2%7D%20%5C%5C%20%3D9%20%5Cend%7Bgathered%7D)
so fourth bush 9 units below of A.
