Answer:
y = 100 - 8(n - 1)
Step-by-step explanation:
I. if n = 1 or 1st year = 100 - 8(1-1) is 100
if n = 2 or 2nd year = 100 - 8(2-1) is 92
if n = 3 or 3rd year = 100 -8(3-1) is 84
Hope it'll help.
Another point on the line is (6,-1)
Answer:
Step-by-step explanation:
c i think
Answer:
15.866%
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 3,282 gallons of kerosene
μ is the population mean = 3,087 gallons of kerosene
σ is the population standard deviation = 195 gallons
For x > 3282 gallons
z = 3282 - 3087/195
z = 1
Probability value from Z-Table:
P(x<3282) = 0.84134
P(x>3282) = 1 - P(x<3282) = 0.15866
Converting to percentage
0.15866 × 100 = 15.866%
The percent of flights on these particular routes that will burn more than 3,282 gallons of kerosene is 15.866%
