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3 years ago

How can Pythagorean theorem be used to find distance in a coordinated plane?

1 answer:

5 0

You can always draw a right-angled triangle where the sloped side c is the line between the two points of interest, and a and b are the sizes of the horizontal and vertical lines.

Then apply c = √(a²+b²)

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Please answer quickly, (1 question, 30 pts) thanks!

kaheart [24]

Step-by-step explanation:

once the level of medicine reaches a value, where 30% are 23mL (so, whatever is lost, is immediately replaced again), that is then the long run value for the amount of the drug in the patient's body.

so,

30% = 23 mL

1% = 30%/30 = 23/30 = 0.766666666...

100% = 1%×100 = 0.766666666... × 100 = 76.666666...

so, once the level reaches 76.666666... mL in the body, it will remain constant, as the daily filtered out 30% are 23 mL, and the daily add-on is also 23 mL.

so, the answer is

76.667 mL

5 0

1 year ago

What are the cubic units? Pleaseee

Ray Of Light [21]

Answer: pls mark me brainiest

Step-by-step explanation:

I am very sure that the answer is V≈351.86

4 0

2 years ago

Read 2 more answers

Type the correct answer in each box. use numerals instead of words. the number of customers who come into julie's antique shop o

vladimir1956 [14]

She will also need the minimum value, the median, the upper quartile and the lower quartile.

The box will be drawn from the upper quartile to the lower quartile, with a vertical line at the median. The whiskers will go from the box to the highest and lowest values.

3 0

2 years ago

Read 2 more answers

Which of the following is most likely the value of the seventh term of the sequence graphed below?

IRISSAK [1]

I think the answer is A. Hope it help!

4 0

2 years ago

Read 2 more answers

6,666,666×666,666 /1+2+3+4+5+6+5+4+3+2+1 − 777,777×777,777/1+2+3+4+5+6+7+6+5+4+3+2+1

jeka57 [31]

Answer:

111111 $\times$ 1111110 is the simple expression.

Step-by-step explanation:

The expression to be solved:

$\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1} - \dfrac{777,777\times777,777}{1+2+3+4+5+6+7+6+5+4+3+2+1}$

First of all, let us solve the first term:

$\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1}\\\Rightarrow \dfrac{6666666\times666666 }{36}\\\Rightarrow \dfrac{6666666\times666666 }{6\times 6}\\\Rightarrow 1111111\times 111111$

Now, the right term:

$\dfrac{777777\times777777}{1+2+3+4+5+6+7+6+5+4+3+2+1}\\\Rightarrow \dfrac{777777\times777777}{49}\\\Rightarrow \dfrac{777777\times777777}{7 \times 7}\\\Rightarrow 111111 \times 111111$

So, the expression to be solved becomes:

$1111111\times 111111-111111\times 111111\\\Rightarrow 111111(1111111-1)\\\Rightarrow 111111\times 1111110$

3 0

3 years ago