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Lera25 [3.4K]
3 years ago
10

Somebody please help me out quick ??

Mathematics
2 answers:
mylen [45]3 years ago
7 0
S= 26/2=13.
√13(2)(4)(7)
√13(56)
√728.
= 26.98.
The answer is 27.
scoundrel [369]3 years ago
6 0
38 i think is correct

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A physical education department wanted a single test of upper body strength that was easy to administer. Dips on the parallel ba
Gennadij [26K]

Answer:

24.23 ; 13.47 ; 0.782 ; p value < 0.00001 ;7.45

Step-by-step explanation:

Given that :

ΣX = 3,416, ΣY = 1,899, SDX = 8.84, SDY = 4.70, ΣZXZY = 109.416

Sample size, N = 141

Mean of X:

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Mean of Y:

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B.) Correlation between the 2 variables :

£ZXZY / N - 1

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= 0.782

C.)

Level of significance and p value :

T = [Rsqrt(n-2)] ÷ sqrt(1 - R²)

T = [0.782 * sqrt(139)] ÷ sqrt(1-0.782^2)

T = 14.79

P value from Tscore calculator

Df = 141 - 2 = 139 ; α = 0.05

Pvalue = 0.00001

Pvalue < α ; Hence, a significant positive relationship exists.

To obtain regression model :

Slope = £ZXZY / SDX²

m = 109.416 / 8.84^2 = 1. 4

yintercept = meanY - slope*x

yintercept = 13.47 - 1.4*24.3

yintercept = - 20.55

Equation in slope intercept form:

y = mx + c

y = 1.4x - 20.55

For x = 20

y = 1.4(20) - 20.55

y = 7.45

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