First lets distribute the 5x
5x^2 + 30x = -50
Lets divide every term by 5
x^2 + 6x = -10
To complete the square we have to half the b value, which in this case is 6. Then square it.
Half of 6 is 3, 3 squared is 9
Add that to both sides of the equation
x^2 + 6x + 9 = -1
Find the binomial squared
(x+3)^2 (If you're wondering how i got that please comment)
(x+3)^2 = -1
Take the square root of the equation of both sides
(x+3) = +/- i
x = -3 +/- i
x = -3 - i
and
x = -3 + i
Positive sorry if it’s wrong good luck
The length of GQ is 2 1/3 (two and one-third) where x equals -2/3 (negative two-thirds).
seperable differential equations will have the form
what you do from here is isolate all the y terms on one side and all the X terms on the other
just divided G(y) to both sides and multiply dx to both sides
then integrate both sides
once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it
In your problem,
so all you need to integrate is
