Solve 1/2y+5−3/4y=0.

A triangle has side lengths of 7.1, 12.6, and b. Which of the following CANNOT be b? (A) 5.7 (B) 7.5 (C) 10.1 (D) 18.5 (E) 19.9

GuDViN [60]

-- When the 7.1 and 12.6 sides both point in exactly the same direction,
their open ends are 5.5 apart. So the missing side must be greater than 5.5 .
All of the choices are greater than 5.5 , so we haven't found it yet.

-- When the 7.1 and 12.6 point in opposite directions, their open ends are
19.7 apart. So the missing side can't be greater than 19.7, otherwise the
two sides we know couldn't reach between its ends. Choice 'E' is greater
than 19.9, so it can't be the missing side.

8 0

2 years ago

Label the equations in number 5-7 as True or False:

kkurt [141]

Answer:

${ \rm{ {(7}^{1}) ^{9 } = 7 {}^{5} \times {7}^{5} : \: { \tt{ \red{false}}} }} \\{ \boxed{ \mathfrak{correction \dashrightarrow \: ( {7}^{1}) {}^{9} = {7}^{9} }}} \\ \\ { \rm{ \frac{ {y}^{13} }{ {( {y}^{2}) }^{6} } = {y}^{ - 10} \times {y}^{9} : \:{ \tt { \red{false}}}}} \\ { \boxed{ \mathfrak{correction \: \dashrightarrow \: { \rm{{y}^{1} }}}}} \\ \\ { \rm{ {b}^{4} \times {b}^{ - 6} = \frac{ {b}^{1} \times {b}^{3} }{ {b}^{6} } }} \: : \: { \tt{ \green{true}}}$

8 0

2 years ago

Read 2 more answers

Solve h = −16t2 + 36t + 4.

kvasek [131]

I can do each of the things I asked above.
So, let's change this into vertex form:
$h=-16t^2+36t+4$
$h=(-16t^2+36t)+4$
$h=-16(t^2-2.25t)+4$
$h=-16(t^2-2.25t+1.27-1.27)+4$
$h=-16(t^2-2.25t+1.27)+20.32+4$
$h=-16(t-1.125)^2+24.32$
The vertex is at (1.125,24.32)
Answers may vary due to rounding

Factored Form:
$h = -16t^2 + 36t + 4$
$h = -4\left(4t^2-9t-1\right)$

Quadratic Formula:
$x = \frac{-b +/- \sqrt{b^2-4(a)(c)}}{2a}$
h = -16t^2 + 36t + 4
a = -16 b = 36 c = 4
$h = \frac{-(36) +/- \sqrt{(36)^2-4(-16)(4)}}{2(-16)}$
$h = \frac{-36 +/- \sqrt{1552}}{-32}$
$h = ≈-0.11$
$h = ≈2.36$

5 0

2 years ago

Eric created a rectangular patio using 1 foot square paving stones which are sold in batches by the Dozen the patio measures 7 f

Verdich [7]

Eric need 5 batches of paving stones to created his patio.

6 0

2 years ago

In a standard deck of cards there 52 cards of which 26 are black and 26 are red. Additionally, there are 4 suits, hearts, clubs,

stich3 [128]

Using probability concepts, it is found that P(S and D) = 0.1275.

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A probability is the number of desired outcomes divided by the number of desired outcomes.
In a standard deck, there are 52 cards.
Of those, 13 are spades, and 13 are diamond.

The probability of selecting a spade with the first card is 13/52. Then, there is a 13/51 probability of selecting a diamond with the second. The same is valid for diamond then space, which means that the probability is multiplied by 2. Thus, the desired probability is:

$P(S \cap D) = 2 \times \frac{13}{52} \times \frac{13}{51} = \frac{2\times 13 \times 13}{52 \times 51} = 0.1275$

Thus, P(S and D) = 0.1275.

A similar problem is given at brainly.com/question/12873219

7 0

2 years ago