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shutvik [7]
3 years ago
11

Instructions:Select the correct answer from each drop-down menu. A bird catches a fish, flies 100 yards upward in a straight lin

e, and then drops the fish. The fish lands at a spot that is 50 yards horizontally from the point where the bird caught it. The bird flies at an angle of degrees from the ground, and its height from the ground when it drops the fish is yards.

Mathematics
2 answers:
Shalnov [3]3 years ago
6 0

Answer:

1. B:  60

2. B: 86.6

Hope this helps ;)

Step-by-step explanation:

Romashka [77]3 years ago
5 0

This is the answer on my test. this is correct.

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Liza comes to the swimming pool once every 6 days. Jenny comes once every 4 days and Olga comes once every 10 days. This Monday
a_sh-v [17]

Answer:

Step-by-step explanation: 60 days

7 0
3 years ago
This hyperbola is centered at theorigin. Find its equation.Foci: (-2,0) and (2,0)Vertices: (-1,0) and (1,0)
beks73 [17]

SOLUTION

From the question, the center of the hyperbola is

\begin{gathered} (h,k),\text{ which is } \\ (0,0) \end{gathered}

a is the distance between the center to vertex, which is -1 or 1, and

c is the distance between the center to foci, which is -2 or 2.

b is given as

\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}

But equation of a hyperbola is given as

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

Substituting the values of a, b, h and k, we have

\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}

Hence the answer is

\frac{x^2}{1}-\frac{y^2}{3}=1

5 0
1 year ago
The triangles shown below must be congruent.
Anestetic [448]

Answer:

Yes the triangles are congurant.

Step-by-step explanation:

Because if you can see up and down triangles this means they are congurent.

4 0
3 years ago
Solve the equation. 3x + 5 = x - 3
Luden [163]

Answer:

x=-4

Step-by-step explanation:

Subtract x from 3x ( 2x )

2x+5=-3

Subtract 5 from -3 ( -8 )

2x=-8

Divide ( -4 )

x=-4

3 0
2 years ago
Identify the vertical asymptotes of f(x) = 2 over quantity x squared plus 3 x minus 10.
zysi [14]
The function is:
f ( x ) = 2 / ( x² + 3 x - 10 )
x² + 3 x - 10 = x² + 5 x - 2 x - 10 = x ( x + 5 ) - 2 ( x + 5 ) =
= ( x + 5 ) ( x - 2 )
x + 5 = 0 => x = - 5
x - 2 = 0 => x = 2
Answer:
The vertical asymptotes are: x = - 5 and x = 2.
3 0
3 years ago
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