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belka [17]
2 years ago
5

Please help me ASAP NO LINKS or files

Mathematics
1 answer:
Bess [88]2 years ago
4 0

Answer:

1 (-9, -4)

2 (-6, 2)

Step-by-step explanation:

1- when you reflect along the x axis keep the x the same and change the y.

2- when you reflect along the y axis keep the y the same and change the x.

You might be interested in
Evaluate the expression for x=-6 4more than the product of-4 and the number ​
son4ous [18]

Answer:

28

Step-by-step explanation:

The product of -4 and the unknown number n is -4n.

4 more than the product of -4 and the unknown number n is -4n + 4.

Letting n = -6 results in the value  -4(-6) + 4, or 24 + 4, or 28.

8 0
3 years ago
What is the perimeter of △ABC?
timofeeve [1]
<h3>Given</h3>
  • ΔABC
  • A(-3, -1), B(0, 3), C(1, 2)
<h3>Find</h3>
  • the length of the perimeter of ΔABC to the nearest tenth
<h3>Solution</h3>

The perimeter of a triangle is the sum of the lengths of its sides. The length of each side can be found using the Pythagorean theorem. Effectively, each pair of points is treated as the end-points of the hypotenuse of a right triangle with legs parallel to the x- and y-axes. The leg lengths are the differences betweeen the x- and y- coordinates of the points.

The difference of the x-coordinates of segment AB are 0-(-3) = 3. The y-coordinate difference is 3-(-1) = 4. So, the leg lengths of the right triangle whose hypotenuse is segment AB are 3 and 4. The Pythagorean theorem tells us

... AB² = 3² +4² = 9 +16 = 25

... AB = √25 = 5

You may recognize this as the 3-4-5 triangle often introduced as one of the first ones you play with when you learn the Pythagorean theorem.

LIkewise, segment AC has coordinate differences of ...

... C - A = (1, 2) -(-3, -1) = (4, 3)

These are the same leg lengths (in the other order) as for segment AB, so its length is also 5.

Segment BC has coordinate differences ...

... C - B = (1, 2) -(0, 3) = (1, -1)

The length of the line segment is figured as the root of the sum of squares, even though one of the coordinate differences is negative. The leg lengths of the right triangle used for finding the length of BC are the absolute value of these differences, or 1 and 1. Then the length BC is

... BC = √(1² +1²) = √2 ≈ 1.4

So the perimeter of the triangle ABC is

... AB + BC + AC = 5 + 1.4 + 5 = 11.4 . . . . perimeter of ∆ABC in units

_____

Please be aware that the advice to "round each step" is <em>bad advice,</em> in general. For real-world math problems, you only round the final result. You always carry at least enough precision in the numbers to ensure that there will not be any error in the final rounding.

In this problem, the only number that is not an integer is √2, so it doesn't really matter.

7 0
3 years ago
Consider a parallelogram with vertices at (0, 3), (2, 0), (4, 2), and (2, 5).
goldenfox [79]

Answer:

B

Step-by-step explanation:

So a reflection over the x is a change in the y value.

Only point (2,0) is on the x-axis, so it will not move.

4 0
2 years ago
. mrs. opsahl drove 399 miles on 14 gallons of gas. how many miles per gallon did her car get? 0.27 miles per gallon 28.5 miles
Dennis_Churaev [7]

Answer:

28.5 miles per gallon

Step-by-step explanation:

399 miles / 14 gallons

= 28.5 miles/1 gallon

1 gallon per 28.5 miles

8 0
2 years ago
What is the focus of the parabola given the equation y=x^2+4x-1
IrinaK [193]
Let's first rewrite it in vertex form.
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5

Now, 4a = 1; a = \frac{1}{4}

So, the vertex form is (x + 2)² = 4(\frac{1}{4})(y + 5)
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.

∴ F(-2, -5 + \frac{1}{4})
F(-2, \frac{-19}{4})
3 0
3 years ago
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