Answer:
[8i + 54j + 72k] joules per newton metre square.
Step-by-step explanation:
F(x,y,z) = z2i + 3xyj + 3y2k
F(3,0,0) = 0
F(3,3,1) = 1(2i) + 3(3)(3)j + 3(3)(2k)
= 2i + 27j + 18k
F(0,3,1) = 1(2i) + 3(0)(3)j + 3(3)(2k)
= 2i + 18k
The sum = [4i + 27j + 36k]
Since the particle moves back to the origin, we multiply the above Work Done by 2:
[8i + 54j + 72k]
And since work done is the product of Force and Distance, the S.I. unit is Joules/newton metre square
