The formula for the area of the shaded region in the figure.
x² = 4py is mathematically given as
<h3>What is the formula for the area of the shaded region in the figure?</h3>
Parameters
Generally, the equation for the Area is mathematically given as
![& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\](https://tex.z-dn.net/?f=%26%20A%3D2%20%5Cint_%7B0%7D%5E%7B2%20%5Csqrt%7Bp%20h%7D%7D%5Cleft%28h-%5Cfrac%7Bx%5E%7B2%7D%7D%7B4%20p%7D%5Cright%29%20d%20x%20%5C%5C%5C%5C%26%20A%3D2%5Cleft%28h%20x-%5Cfrac%7Bx%5E%7B3%7D%7D%7B12%20p%7D%5Cright%5D_%7B0%7D%5E%7B2%20%5Csqrt%7Bp%20h%7D%7D%20%5C%5C%5C%5C%26%20A%3D2%5Cleft%5B%5Cleft%5Bh%202%20%5Csqrt%7Bp%20h%7D-%5Cfrac%7B1%7D%7B12%20p%7D%20%5Ccdot%282%20%5Csqrt%7Bp%20h%7D%29%5E%7B3%7D-0%5Cright%5D%5Cright.%20%5C%5C)
![&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h](https://tex.z-dn.net/?f=%26A%3D2%5Cleft%5B2%20h%5E%7B3%20%2F%202%7D%20%5Csqrt%7Bp%7D-%5Cfrac%7B8%28%5Csqrt%7Bp%7D%29%5E%7B3%7D%28%5Csqrt%7Bh%7D%29%5E%7B3%7D%7D%7B12%20p%7D-0%5Cright%5D%20%5C%5C%5C%5C%26A%3D2%5Cleft%5B2%20h%5E%7Bk%20%2F%202%7D%20%5Csqrt%7Bp%7D-%5Cfrac%7B2%7D%7B3%7D%20%5Csqrt%7Bp%7D%20%5Ccdot%20h%5E%7B3%20%2F%202%7D%5Cright%5D%20%5C%5C%5C%5C%26A%3D2%20%5Ctimes%20%5Cfrac%7B4%20%5Csqrt%7Bp%7D%20%5Ccdot%20h%5E%7B3%20%2F%202%7D%7D%7B3%7D%20%5C%5C%5C%5C%26A%3D%5Cfrac%7B8%7D%7B3%7D%20%5Ccdot%20%5Csqrt%7Bp%7D%20%5Ccdot%20%5Csqrt%7Bh%7D%20%5Ccdot%20h%20%5C%5C%5C%5C%26A%3D%5Cfrac%7B8%7D%7B3%7D%20%5Csqrt%7Bp%20h%7D%20%5Ccdot%20h)
In conclusion, the equation for the Area is
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Answer:
if ∠Q=∠R
draw an angular bisector from P to QR in which it intersect wit Qr at point S
now we have two triangle : QPS and RSP
in which angle : QPS=RPS ( PS is angular bisector)
and we have angle Q and angle R are equal
and PS is common side
this makes triangle QPS and RSP are congruent by AAS(angle angle side)
which also means that pQ=PR ( proved)
All you have to do is multiply both
Answer:
67
Step-by-step explanation:
You have to use fractions to show your work and I'm not going to do that but just know that it is the answer.
Answer:
<u><em>y=7 </em></u><u>number of hours at grocery store</u>
<u><em>x=18 </em></u><u>number of hours at baby- sitting</u>
Step-by-step explanation:
According to the information provided.
x is number of hours at baby- sitting
y is number of hours at grocery store
total number of hours worked
<em>1) </em><em>x+y =25</em>
total earn in a week
<em>2) </em><em>x*$6 + y* $9 = $171</em>
<em />
<em>from equation 1</em>
x+y=25
x= 25-y
<em>we place the above derived equation in equation 2 </em>
x*$6 + y* $9 = $171
(25-y)*$6 + y* $9 = $171
(25*6) -6y +9y =171
150+3y=171
3y=171-150
3y=21
<u><em>y=7 </em></u><u>number of hours at grocery store</u>
x= 25-y
x= 25-7
<u><em>x=18 </em></u><u>number of hours at baby- sitting</u>
