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2 years ago

Determine weather the function shown in the graph is even or odd.....will give brainlest

Mathematics

1 answer:

Nitella [24]2 years ago

7 0

A function with a graph that is symmetric about the origin is called an odd function. Note: A function can be neither even nor odd if it does not exhibit either symmetry.
If a function is even, the graph is symmetrical about the y-axis. If the function is odd, the graph is symmetrical about the origin.

So in this graph you have, the function shown in the graph is even.

Hope this help! Mark me brainliest please:)

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Subtract:

Shtirlitz [24]

Answer:

Step-by-step explanation:

(3x³ - 10x² + 13x) - (5x³ + 4x² - 9x)

3x³ - 10x² + 13x - 5x³ - 4x² + 9x Change all terms after the subtraction sign to

the opposite sign (definition of Subtraction)

(3x³ - 5x³) + (-10x² - 4x²) + (13x + 9x) Group like terms together

-2x³ - 14x² + 22x

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2 years ago

What is the width of a box when the length is x+2, the height is x+8, and the volume is x^3+9x^2+6x-16?

Nostrana [21]

(x+2)(x+8) = x^2 +10x +16

(x^2 + 10x + 16)(x-1) = x^3+9x^2+6x-16, so the other dimension is x-1

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3 years ago

Read 2 more answers

Can someone please help im struggling

NNADVOKAT [17]

Answer:

81 units³

Step-by-step explanation:

V = Length x Widht x Height

= 9 x 3 x 3

= 81 units³

5 0

3 years ago

Write two properties of right angled triangle

leonid [27]

Answer:

The properties of right angle triangle are as follows

the hypotenuse is the longest side
one angle is 90 degree then other angle will be also 90 degree.

5 0

2 years ago

A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o

Mandarinka [93]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = 22 ounces

Alternate Hypothesis, $H_A$ : $\mu\neq$ 22 ounces

(b) The value of the test statistic is -2.687.

(c) The critical values are -1.96 and 1.96.

(d) We conclude that Reject $H_0$ since the value of the test statistic is less than the negative critical value.

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle.

He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

Let $\mu$ = average ounces of passion fruit juice used to fill each bottle.

(a) So, Null Hypothesis, $H_0$ : $\mu$ = 22 ounces {means that the average of 22 ounces of passion fruit juice is used to fill each bottle}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 22 ounces {means that the average different from 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weight of the passion fruit juice = 21.54 ounces

$\sigma$ = population standard deviation = 1.38 ounce

n = sample of bottles = 65

So, test statistics = $\frac{21.54-22}{\frac{1.38}{\sqrt{65} } }$

= -2.687

(b) The value of z test statistics is -2.687.

(c) Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that Reject $H_0$ since the value of the test statistic is less than the negative critical value which means that the average different from 22 ounces of passion fruit juice is used to fill each bottle.

6 0

3 years ago