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Jet001 [13]
2 years ago
15

Determine weather the function shown in the graph is even or odd.....will give brainlest

Mathematics
1 answer:
Nitella [24]2 years ago
7 0
A function with a graph that is symmetric about the origin is called an odd function. Note: A function can be neither even nor odd if it does not exhibit either symmetry.
If a function is even, the graph is symmetrical about the y-axis. If the function is odd, the graph is symmetrical about the origin.

So in this graph you have, the function shown in the graph is even.

Hope this help! Mark me brainliest please:)
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Step-by-step explanation:

For any function to be defined at a particular value, it should not be <em>approaching to a value </em>\infty<em> or it should not give us the </em>\frac{0}{0}<em> (zero by zero) form </em> when the input is given to the function.

The value of function will depend on the denominator.

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2.\ \dfrac{18}{y}

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So, the given function is <em>defined for all real numbers except y = 0</em>

<em></em>

<em></em>3.\ \dfrac{1}{x+7}<em></em>

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x + 7 can be zero at a value x = -7

At\ x =-7,  \dfrac{1}{x+7} \rightarrow \infty

So, the given function is <em>defined for all real numbers except x = -7</em>

<em></em>

4.\ \dfrac{2b}{10-b}

Let us consider denominator:

10-b can be zero at a value b = 10

At\ b =10,  \dfrac{2b}{10-b} \rightarrow \infty

So, the given function is <em>defined for all real numbers except b = 10</em>

<em></em>

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