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Murljashka [212]
3 years ago
7

Which statement below is ALWAYS TRUE?

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0

Answer is C because they are next to each other in 180 degree angles or 90 degrees angles

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The volume of a right circular cone is found using the equation V = 1 3 π r 2 h . Which equation represents the volume solved fo
alex41 [277]

Solving for a variable in an equation means, we are changing the subject of formula of the equation.

The equation of r is: \mathbf{r = \sqrt{\frac{3V}{\pi h}}}

The equation is given as:

\mathbf{V = \frac 13 \pi r^2h}

We start by multiplying both sides by 3

\mathbf{V \times 3= \frac 13 \pi r^2h \times 3}

Rewrite as:

\mathbf{3V= \pi r^2h}

Divide both sides by \mathbf{\pi h}

\mathbf{\frac{3V}{\pi h}= \frac{\pi r^2h}{\pi h}}

Cancel out common factors

\mathbf{\frac{3V}{\pi h}= r^2}

Take square roots of both sides

\mathbf{\sqrt{\frac{3V}{\pi h}}= \sqrt{r^2}}

Evaluate the right-hand sides

\mathbf{\sqrt{\frac{3V}{\pi h}}= r}

Make r the subject

\mathbf{r = \sqrt{\frac{3V}{\pi h}}}

Hence, the resulting equating for r is:

\mathbf{r = \sqrt{\frac{3V}{\pi h}}}

Read more about the subject of formulas at:

brainly.com/question/21866313

6 0
2 years ago
Missing angles in triangle help
Dmitry [639]

Answer:

which one?

Step-by-step explanation:

6 0
3 years ago
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Given the following matrices A and B, find an invertible matrix U such that UA = B:
Naddik [55]

<span>A and B must be invertible, we have UA=B, since A is invertible.  A^-1 exists, by multiplying with A^-1, we have UA A^-1 =B A^-1. But AA^-1 = I (identity matrix) and XI=X, for all matrix X, we find UI= B A^-1, and U= B A^-1.</span>

3 0
3 years ago
Help I have one day to do this pleaseeeeeee
Sonbull [250]
I’m pretty sure the answer is c.

Since each I guess ‘layer, or cubes will have 12 cubes.

The height is 4

12*4=48

I hope this helps, I’m really sorry if the answer is wrong
6 0
3 years ago
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The graph is of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?
Reika [66]

The real solutions of f(x) = 0 is; x = -8, 0 and 4

<h3>How to find the roots of a polynomial graph?</h3>

When talking about real solutions of a polynomial, we are simply referring to the values of x that make the polynomial f(x) = 0.

Now, in a polynomial graph as attached, the real solutions are the roots and they are the values of x where the curve crosses the x-axis.

From the given graph, the real solutions are at x = -8, 0 and 4

Thus, we conclude that the real solutions of f(x) = 0 is; x = -8, 0 and 4

Read more about Polynomial roots graph at; brainly.com/question/14625910

#SPJ1

8 0
1 year ago
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