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3 years ago

Alex and Peter win some money and share it in the ratio 3:5. Alex gets £33. How much did Peter get?

Mathematics

1 answer:

IgorLugansk [536]3 years ago

5 0

Answer:

Step-by-step explanation:

Set it up as fractions, Alex over Peter.

3/5 : 33/x Let x represent Peter's amount. Now find out: how do you get from 3 to 33? What times 3 equals 33? 11

What you do on the top, you must do on the bottom. If 3 times 11 equals 33, then 5 times 11 equals x. 5 times 11 equals 55, so x equals 55.

Peter will get 55. Don't forget the pound symbol.

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What is the simplified form of the expression-4xy/3x Show your work

kogti [31]

Answer:

-4y/3

Step-by-step explanation:

If we have -4xy/3x, we just cancel the x since it is in the numerator and denominator. That leaves us with just -4y/3

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3 years ago

Can someone check my work?. 1. Simplify the given expression.. (7 − 3i) • (2 − i) . 4 + i (MY ANSWER) . . 14 + 3i . . 11 − 13i .

Annette [7]

1. (7 − 3i) • (2 − i)
It is simplified as follows:
14 - 7i -6i - 3
11 - 13i

2. (−5 + 3i) • (1 − 2i)
It is simplified as follows:
-5 + 10i + 3i + 6
1 + 13i

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It is simplified as follows:
1 + 3i + 2 − 5i
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6 + 2i − 8 + 3i
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4 0

3 years ago

Please put your answer in simplest form 1/2 + 1/3 + 1/4 + 1/5 + 1/6 = ?

Norma-Jean [14]

Pretty sure the answer is 29/20 or 1 9/20. You get this by find the common denominator , 60, and then adding the number all together and simplifying

6 0

3 years ago

Read 2 more answers

Robert went to the grocery store and purchased cans of soup and frozen dinners. each can of soup has 300 mg of sodium and each f

Paraphin [41]

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Step-by-step explanation:

Let,

Soup = x

Frozen Dinner = y

According to given statement of sodium;

300x + 500y = 5200 eqn 1

And,

x + y = 14 eqn 2

$Multiplying\ equation\ 2\ with\ 300\\300(x+y=14)\\300x+300y=4200\ Eqn 3\\$

Subtracting Eqn 3 from Eqn 1;

$(300x+500y)-(300x+300y)=5200-4200\\300x+500y-300x-300y=1000\\200y=1000\\y=\frac{1000}{200} \\y=5$

Putting value of y in Eqn 1;

$300x+500(5)=5200\\300x+2500=5200\\\\Subtracting\ 2500\ from\ both\ sides\ \\300x+2500-2500=5200-2500\\300x=2700\\x=\frac{2700}{300} \\x=9$

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Keywords: Variables, linear equations, subtraction.

Learn more about linear equations at;

#LearnwithBrainly

5 0

3 years ago

The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n

GarryVolchara [31]

Answer:

$(-1,1),(4,-2)$

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point $(x,y)$

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}$

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

$34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]$

Put $(x,y)=(-1,1)$

$34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34$

which is true. So, $(-1,1)$ can be a vertex

Put $(x,y)=(4,-2)$

$34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34$

which is true. So, $(4,-2)$ can be a vertex

Put $(x,y)=(1,1)$

$34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22$

which is not true. So, $(1,1)$ cannot be a vertex

Put $(x,y)=(2,-2)$

$34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22$

which is not true. So, $(2,-2)$ cannot be a vertex

Put $(x,y)=(4,-1)$

$34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30$

which is not true. So, $(4,-1)$ cannot be a vertex

Put $(x,y)=(-1,4)$

$34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70$

which is not true. So, $(-1,4)$ cannot be a vertex

So, possible points for the vertex are $(-1,1),(4,-2)$

7 0

3 years ago

Read 2 more answers