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garik1379 [7]
3 years ago
15

Send your answers I will check if it is correct

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

Answer:

285, 7392, 15708, are divisible by 3 but not by 9

Step-by-step explanation:

it's because of we add the sun of the digits, 285, 7392, 15708, they are divisible by 3. actually, except for 629, all of them are divisible by 3, but 5490 and 43695 are both divisible by 3 and 9

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What is a hectoliter?<br><br> 1,000 liters<br> 100 grams<br> 1/100 of a liter<br> 100 liters
erma4kov [3.2K]

Answer:

100 litres

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the solution to the absolute value<br> equation shown below.<br><br> |9 + 8x|= 25
Savatey [412]

Answer:

25-9

=16

16:8

=2

x=2

Başarılar

4 0
3 years ago
A piece of wire 10 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
Luda [366]

The maximum and the minimum total area inclosed are 6.25m² and 2.72m²

What is an area?

⇒ The area is the region bounded by the shape of an object.

Calculation:

Let x is the length of the piece of wire for the equilateral triangle, whose side will then be (x/3) m long.

⇒  (10 - x) = length of the remaining piece for the square, whose side will then be (10 - x)/4 m long.

h = height of the equilateral triangle = h = a×√3/2 = (x/3)×(√3/2)

(Where a is the side of the triangle)

A(x) = Total area of the square formed + Total area of the triangle formed

Then    A(x) = [(10 - x)/4]²+ (1/2)(x/3)(x/6)√3

                   = [(100 - 20x + x²)/16] +  (√3/36)x² .

           

The maximum total area enclosed :

⇒ The entire 10m length should be allocated to the square because a square produces more area per unit of its perimeter than does a triangle.

Thus if all square, then x=0 and A(0)  = [2.5]² = 6.25 m² = Maximumarea

If all triangle, then x = 10  and  A(10) = (1.732/36)(100) = 4.811 m² .

So, the maximum area occurs when it's all used to make a square of side 2.5 m.

The minimum total area enclosed is :

⇒ We want a relatively small square and a small triangle.

 We are going to Find x by setting the derivative of A(x) to zero.

d[ A(x)]/dx  =   [(-20 + 2x)/16] + (2√3/36)x = 0

                  =  -5/4  + (1/8)x  +  (√3/18)x  = 0

                 x =  5/[4 (1/8 + √3/18)]  = 5/[ 4(0.125 + 0.09622)] = 5/(0.88489)  ⇒5.65 m perimeter of the triangle                  

             

and (10 - x) = 4.35 = perimeter of square

And  

A(5.65) = [4.35/4]² +  (√3/36)(5.65)²

             = 1.1827 from the square+1.5358 from the triangle

             =  2.719m² total area = Minimum area

⇒ On rounding off it will be 2.72m²

Hence the maximum and the minimum areas are 6.25m² and 2.72m²

Learn more about the area here:

brainly.com/question/25292087

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Questions:  A piece of wire 10m long is cut into two pieces. one piece is bent into a square and the other is bent into an equilateral triangle. How should the wire be cut so that the total area enclosed is a. a maximum? b. minimum?

8 0
2 years ago
One golfer's scores for the season are 88, 90, 86, 89, 96, and 85. Another
Allisa [31]

Mean of the first golfer = 89

Mean of the second golfer = 87

Range of the first golfer = 11

Range of the second golfer = 8

Explanation:

First golfer scores 88, 90, 86, 89, 96 and 85.

Sum of the scores of first golfer = 88 + 90 + 86 + 89 + 96 + 85 = 534

Number of observation of first golfer = 6

\text {Mean} = \frac{\text {Sum of the observation}}{\text {Number of observation}}

Mean of the first golfer = \frac{534}{6}=89

Mean of the first golfer = 89

Range of the first golfer = Highest score – Lowest score

                                        = 96 – 85

Range of the first golfer = 11

Second golfer scores 91, 86, 88, 84, 90 and 83.

Sum of the scores of second golfer = 91 + 86 + 88 + 84 + 90 + 83 = 522

Number of observation of second golfer = 6

\text {Mean} = \frac{\text {Sum of the observation}}{\text {Number of observation}}

Mean of the second golfer = \frac{522}{6}=87

Mean of the second golfer = 87

Range of the second golfer = Highest score – Lowest score

                                              = 91 – 83

Range of the second golfer = 8

Comparing the golfer's skills:

Mean of first golfer is greater than Mean of second golfer.  (i.e. 89 > 87)

Range of first golfer is greater than Range of second golfer. (i.e. 11 > 8)

Thus, first golfer have more skills than second golfer.

6 0
3 years ago
The length of a rectangle is 13 feet. The width is 9 feet. What is the perimeter of the rectangle?
KatRina [158]
13 + 13 + 9 + 9 = 44 feet.
Please make this answer the brainliest!
7 0
4 years ago
Read 2 more answers
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