Call me when you want, call me when you need
Call me in the morning, I'll be on the way
Call me when you want, call me when you need
Call me out by your name, I'll be on the way like
Answer:
Principal amount (P) = $6000
Rate (R) = 12%
Time = 2 years
Simple interest, I = P X R X T / 100
= 6000 X 12 X 2 / 100
= 144000 / 100
= 1440
=> Simple interest, I = $1440
Amount they would owe at the end of 2 years,
= P + I
= 6000 + 1440
= $7440
3/20 = x/400,
cross multiply
so 20x = 3(400)
20x = 1200
x = 60
Answer:
32.59 (nearest hundredth)
Step-by-step explanation:
<u />
<u>Geometric sequence</u>
General form of a geometric sequence: ![a_n=ar^{n-1}](https://tex.z-dn.net/?f=a_n%3Dar%5E%7Bn-1%7D)
(where a is the first term and r is the common ratio)
Given:
![\displaystyle \sum^{20}_{n=1} 4 \left(\dfrac{8}{9}\right)^{n-1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum%5E%7B20%7D_%7Bn%3D1%7D%204%20%5Cleft%28%5Cdfrac%7B8%7D%7B9%7D%5Cright%29%5E%7Bn-1%7D)
Therefore:
<u>Sum of the first n terms of a geometric series</u>:
![S_n=\dfrac{a(1-r^n)}{1-r}](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Ba%281-r%5En%29%7D%7B1-r%7D)
To find the sum of the first 20 terms, substitute the found values of a and r, together with n = 20, into the formula:
![\implies S_{20}=\dfrac{4\left(1-\left(\frac{8}{9}\right)^{20}\right)}{1-\left(\frac{8}{9}\right)}](https://tex.z-dn.net/?f=%5Cimplies%20S_%7B20%7D%3D%5Cdfrac%7B4%5Cleft%281-%5Cleft%28%5Cfrac%7B8%7D%7B9%7D%5Cright%29%5E%7B20%7D%5Cright%29%7D%7B1-%5Cleft%28%5Cfrac%7B8%7D%7B9%7D%5Cright%29%7D)
![\implies S_{20}=32.58609013...](https://tex.z-dn.net/?f=%5Cimplies%20S_%7B20%7D%3D32.58609013...)