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3 years ago

Examples of a cell wall

2 answers:

7 0

<span>✡ Answer: A example of this is a wall surrounding fungi (a cell wall) </span><span>✡

- - Why?
Because this is a good example of a cell wall, and it is commonly used in most science lessons (in my school atleast)

</span><span>✡Hope this helps</span><span><span>✡ </span>
</span>

LenaWriter [7]3 years ago

6 0

A gate protecting the house inside

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Which of the following is not a base? <br><br> A: NH3<br> B. NaOH<br> C. H3C6H5O7<br> D. KOH

olga2289 [7]

I think that C is the answer.....

7 0

3 years ago

Read 2 more answers

NEED HELP ASAPPP<br><br> What is the number of beryllium atoms in 78.0g of Be?

polet [3.4K]

Answer: number of atoms is 5.21 · 10^24

Explanation: Atomic mass of Be is 9.012 g/mol.

Number of moles n = m/M = 78.0 g / 9.012 g/mol =

Multiply this with Avogadro number Na = 6.022*10^23 1/mol

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3 years ago

Molecule of dissimilar elements with a net charge remaining is called

MariettaO [177]

It is called a polyatomic ion.

Hope this helps!!!

3 0

4 years ago

Identify the products of this single-replacement reaction between sulfuric acid and aluminum. Then balance the equation. (2 poin

jeka94

The products of this reaction between aluminum and sulfuric acid are two: hydrogen and aluminum sulfate.

<h3>What are the products in a reaction?</h3>

This concept refers to the substances obtained at the end of the reaction.

<h3>What does it mean to balance an equation?</h3>

It means to make sure there are the same molecules in the reactants and products.

<h3>What are the products in this reaction?</h3>

Al + H2SO4 = Al2 (SO4)3 + H2
Al2 (SO4)3 = Aluminium sulfate
H = Hydrogen

<h3>What is the balanced equation?</h3>

2Al + 3H2SO4 = Al2 (SO4)3 + 3H2

Learn more about chemical reaction in: brainly.com/question/3461108

7 0

2 years ago

For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.

Veronika [31]

Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

The alcohol used: methanol, CH3OH

The carboxylic acid used: propanoic acid, CH3CH2COOH.

53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

7 0

3 years ago