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3 years ago

Please Help Me! Check if my answer is correct and if not can you please explain the correct answer

Chemistry

1 answer:

Svetlanka [38]3 years ago

7 0

Your answer is not correct.

Correct Answer: 4Fe + 3O2 ——> 2Fe2O3

This is the correct answer because you need equal Iron(Fe) on both sides. Since you already have 2 Irons on the products(right side) side you need 2 on the reactants(left side) side, so you add a 2. For Oxygen(O) since you already have 3 on the products(right) side and only 2 on the reactants(left) side you need to balance those and make them both 6 so you multiply by 2 on the products(right) side and multiply by 3 on the reactants(left) side. Since you can’t add a coefficient to only one element you need to add a 2 to both elements on the product side. So that gets you 4 Iron and 6 Oxygen. On the reactants side you only have 1 Iron and 2 Oxygen. We balance this equation by multiplying by 4 for Iron on the reactants side and multiplying by 3 for Oxygen on the reactants side. So this gets you 4Fe + 3O2 —> 2Fe2O3
I hope this helped!!

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Answer:

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hope it helps 

8 0

2 years ago

Read 2 more answers

A certain substance X has a normal freezing point of -10.1 degree C and a molal freezing point depression constant K_f = 5.32 de

kirill115 [55]

Answer: $-15.4^00C$

Explanation:

$T^0_f-T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = boiling point of solution = ?

$T^o_f$ = boiling point of solvent (X) = $-10.1^oC$

$k_f$ = freezing point constant = $5.32^oC/kgmol$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte like urea)

= mass of solute (urea) = 29.82 g

= mass of solvent (X) = 500.0 g

$M_2$ = molar mass of solute (urea) = 60 g/mol

Now put all the given values in the above formula, we get:

$(-10.1-(T_f))^oC=1\times (5.32^oC/m)\times \frac{(29.82g)\times 1000}{60\times (500.0g)}$

$T_f=-15.4^0C$

Therefore, the freezing point of solution is $-15.4^0C$

7 0

3 years ago

An ionized helium atom has a mass of 6.6 × 10-27 kg and a speed of 5.3 × 105 m/s. It moves perpendicular to a 0.78-T magnetic fi

arsen [322]

Explanation:

In a magnetic field, the radius of the charged particle is as follows.

r = $\frac{mv}{qB}$

where, m = mass, v = velocity

q = charge, B = magnetic field

Therefore, q will be calculated as follows.

q = $\frac{mv}{rB}$

= $\frac{6.6 \times 10^{-27} \times 5.3 \times 10^{5}}{0.014 m \times 0.78 T}$

= $\frac{34.98 \times 10^{-22}}{0.01092}$

= $3.2 \times 10^{-19} \times \frac{1.0 e}{1.6 \times 10^{-19}C}$

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Thus, we can conclude that the charge of the ionized atom is +2e.

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3 years ago

Is the process of a liquid changing into a solid when cooling a chemical reaction?

Alona [7]

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4 years ago

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3 years ago