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lara31 [8.8K]
3 years ago
6

Please Help Me! Check if my answer is correct and if not can you please explain the correct answer

Chemistry
1 answer:
Svetlanka [38]3 years ago
7 0
Your answer is not correct.

Correct Answer: 4Fe + 3O2 ——> 2Fe2O3

This is the correct answer because you need equal Iron(Fe) on both sides. Since you already have 2 Irons on the products(right side) side you need 2 on the reactants(left side) side, so you add a 2. For Oxygen(O) since you already have 3 on the products(right) side and only 2 on the reactants(left) side you need to balance those and make them both 6 so you multiply by 2 on the products(right) side and multiply by 3 on the reactants(left) side. Since you can’t add a coefficient to only one element you need to add a 2 to both elements on the product side. So that gets you 4 Iron and 6 Oxygen. On the reactants side you only have 1 Iron and 2 Oxygen. We balance this equation by multiplying by 4 for Iron on the reactants side and multiplying by 3 for Oxygen on the reactants side. So this gets you 4Fe + 3O2 —> 2Fe2O3
I hope this helped!!
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Write a balanced equation for the complete combustion of 2,3-dimethylbutane. use the molecular formula for the alkane (c before
Nuetrik [128]

2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

<em>Step 1</em>. Write the <em>condensed structural  formula</em> for 2,3-dimethylbutane.

(CH_3)_2CHCH(CH_3)_2

<em>Step 2</em>. Write the <em>molecular formula</em>.

C_6H_14

<em>Step 3</em>. Write the <em>unbalanced chemical equation</em>.

C_6H_14 + O_2 → CO_2 + H_2O

<em>Step 4</em>. Pick the <em>most complicated-looking formula</em> (C_6H_14) and balance its atoms (C and H).

<em>1</em>C_6H_14 + O_2 → <em>6</em>CO_2 + <em>7</em>H_2O

<em>Step 5</em>. Balance the <em>remaining atoms</em> (O).

1C_6H_14 + (<em>19/2</em>)O_2 → 6CO_2 + 7H_2O

Oops! <em>Fractional coefficients</em>!

<em>Step 6</em>. <em>Multiply all coefficients by a number</em> (2) to give integer coeficients..

2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

4 0
3 years ago
Read 2 more answers
A 225 g sample of an unknown solid is heated 67C and placed into a calorimeter containing 25.6 g of water at 15.6°c. If the fina
Stella [2.4K]

Answer:

= 1.271 J/g°C

Explanation:

Heat released by the metal sample will be equivalent to the heat absorbed by  water.

But heat = mass × specific heat capacity × temperature change

Thus;

Heat released by the solid;

= 225 g × c ×(67 -53) , where c is the specific heat capacity of the metal

= 3150 c joules

Heat absorbed by water;

= 25.6 g × 4.18 J/g°C × (53-15.6)

= 4002.0992  joules

Therefore;

3150 c joules = 4002.0992 joules

c =4002.0992/3150

 <u> = 1.271 J/g°C</u>

6 0
3 years ago
Magnesium and iron are metallic elements. How does a mole of magnesium compare with a mole of iron? A mole of iron has more atom
grandymaker [24]

Answer:

They both have the same number of atoms

Explanation:

The number that indicates the amount of particles in a compound is the Avogadro's number (NA).

It does not matter the mass of compound we have, If we have 1 mol we will be sure that we are talking about 6.02×10²³ particles

6.02×10²³ represents the amount of atoms in twelve grams of 12-pure carbon and it is considered a reference to measure the amount of all kinds of substances present in a given system.

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There are three bulbs powered by a battery. What will happen if the middle light burns out.
Vadim26 [7]

Answer:

nuclear war ;P

Explanation:

8 0
3 years ago
Submit What is the solubility of Cd3(POA) 2 in water? (Ksp of Cd3(PO4)2 is 2.5 x 10-33) | 1 2 3 +/- . 0 x100
vesna_86 [32]

<u>Answer:</u> The solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of cadmium phosphate follows:

Cd_3(PO_4)_2\rightleftharpoons 3Cd^{2+}+2PO_4^{3-}

                      3s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Cd^{2+}]^3[PO_4^{3-}]^2

We are given:

K_{sp}=2.5\times 10^{-33}

Putting values in above equation, we get:

2.5\times 10^{-33}=(3s)^3\times (2s)^2\\\\2.5\times 10^{-33}=108s^5\\\\s=1.18\times 10^{-7}mol/L

Hence, the solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

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3 years ago
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