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Allisa [31]
2 years ago
9

Does gene therapy modify DNA

Biology
1 answer:
kramer2 years ago
3 0
Gene therapy is a promising possibility for the treatment of these diseases. With the help of genetically modified viruses, DNA is introduced into cells in order to repair or replace defective genes. By using this method, scientists have discovered a quicker and more efficient treatment for the cells. Hope this helps :)
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Stove:kitchen: as _____ :plant cell.
Kisachek [45]

Answer: Cloroplast

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3 0
3 years ago
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HELP ~~~~~~~~~~Which statement best defines a biodiversity hotspot?
mart [117]

Answer: C

Explanation: I'm not one hundred percent sure I know the context of this question, but biodiversity in an ecosystem means there's a wide variety of organisms, and a hotspot I assume would be an area that has an unusual amount of diversity.

8 0
3 years ago
At each level of a food chain, the biomass of organisms decreases or increases?
Anna007 [38]

It increases because the higher you go in the food chain, the bigger the carnivores or consumers are.

5 0
3 years ago
In chickens the dominant allele Cr produces the creeper phenotype (having short legs). However, the creeper allele is lethal in
Svetllana [295]

Answer:

66.6% of the living progeny would be creepers

Explanation:

The creeper allele is Cr for both parents this means that there is a 50% chance that they will pass the C or r trait to their progeny. In this scenario the deleterious inheritance of rr will be 25% so this will not be factored in this answer. The other progeny is CC 25% and Cr 50% for genotype only

The new calculation for living progeny is this: Of the chances of three living progeny there could be one normal CC and two creepers Cr. This means that 33.3% of the living progeny is normal CC and 66.6% of the living progeny are creepers Cr.

4 0
3 years ago
4. The Rh blood type response system is controlled by the D allele. The genotypes DD and Dd are Rh (Rh positive); dd is Rh- (Rh
DedPeter [7]

Answer:

A - Frequency of D allele = 0.35

Frequency of d allele = 0.65

B- Frequency of DD genotype = 0.1225

Frequency of Dd genotype = 0.455

Frequency of dd genotype = 0.425.

C - Total population = 400

Frequency of heterozygous population = 400*0.455 = 183.

EXPLANATION:

The equilibrium sum of all the allelic frequency of a gene is always 1 and sum of all the genotypic frequency of all the genotype is always 1 - This is according to Hardy-Weinberg.

So p+q =1

p2+ 2pq+q2 =1

where p = frequency of dominant allele

q is the frequency of the recessive allele.

from the question, it was given that there were  170 individual out of 400, which were Rh- negative,

So q2 = 170/400 = 0.425

q= 0.65

Also p+q =1

so p = 1-q

or p = 1-0.65

Hence p =0.35

Frequency of homozgupus for D allele = 0.35*0.35 = 0.1225

Frequency of heterozygous or Dd will be 2pq.

or 2*0.35*0.65 = 0.455

A - Frequency of D allele = 0.35

Frequency of d allele = 0.65

B- Frequency of DD genotype = 0.1225

Frequency of Dd genotype = 0.455

Frequency of dd genotype = 0.425.

C - Total population = 400

Frequency of heterozygous population = 400*0.455 = 183.

8 0
3 years ago
Read 2 more answers
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