5w=30
5w/5=30/5
w=6
Therefore w is equal to 6
        
             
        
        
        
Fiftty two dived by eight is six point five not for sure .
        
             
        
        
        
Answer:
 
And using a calculator, excel or the normal standard table we have that:
 
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  
Solution to the problem
Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:
 
  
Where  and
 and  
Since the distribution for X is normal then we know that the distribution for the sample mean  is given by:
 is given by:
 
We can find the individual probability like this:
 
And using a calculator, excel or the normal standard table we have that:
 
 
        
             
        
        
        
Answer:
y = (-1/2)x + 9/2
Step-by-step explanation:
the equation of a straight line can be written as;
y = mx + c ......1
Where;
m = slope 
c = intercept
For two lines to be perpendicular their slope must be opposite reciprocal of each other.
m1 × m2 = -1 .....2
Given;
The equation Contains (3, 3); and perpendicular to the line y = 2x - 1
Slope of the given equation m1 = 2
Slope of the line m2; substituting m1 to equation 2.
2 × m2 = -1
m2 = -1/2
So, 
y = (-1/2)x + c
To solve for c, let's substitute the given point on the line; (3,3).
3 = (-1/2)(3) + c
3 = -3/2 + c
c = 3 + 3/2
c = 9/2
Therefore, the equation of the line that has the given properties is;
y = (-1/2)x + 9/2
 
        
             
        
        
        
Answer:
C = 5.25 + 0.50H
Step-by-step explanation:
gah, I'm never sure how to explain my work in these sorts of problems. hopefully I was able to help anyways!