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1 year ago

Find the measure of arc FD

Mathematics

1 answer:

Mekhanik [1.2K]1 year ago

3 0

Answer: 49 degrees

Step-by-step explanation:

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Question 8 of 25<br> Which of the following is the quotient of the rational expressions shown here?

Alla [95]

Answer:

B. (5x+5)/(x²-2x)

Step-by-step explanation:

As with numerical fractions, division by a rational expression is equivalent to multiplication by its reciprocal.

<h3>As a multiplication problem</h3>

$\dfrac{5}{x-2}\div\dfrac{x}{x+1}=\dfrac{5}{x-2}\times\dfrac{x+1}{x}$

<h3>Product of rational expressions</h3>

As with numerical fractions, the product is the product of numerators, divided by the product of denominators.

$=\dfrac{5(x+1)}{x(x-2)}=\boxed{\dfrac{5x+5}{x^2-2x}}$

4 0

1 year ago

Please Help. 25 points. <br>

vodomira [7]

Answer:

$\boxed{x = 7, y = 9, z = 68}$

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

$\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}$

$\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}$

$\boxed{\mathbf{ x = 7, y = 9, z = 68}}$

4 0

2 years ago

Work out the inverse function <br><br>y=x-2

AURORKA [14]

Answer:

x + 2

Step-by-step explanation:

Replace the x with y.

Making is x = y -2

Solve for x=y-2

and you get x+2

7 0

1 year ago

Read 2 more answers

-2x-y=-9<br> 5x-2y=18<br> substitution

KIM [24]

$-2x-y=-9 \\
5x-2y=18 \\ \\
\hbox{solve the first equation for y:} \\
-2x-y=-9 \ \ \ |+2x \\
-y=-9+2x \ \ \ |\times (-1) \\
y=9-2x \\ \\
\hbox{substitute 9-2x for y in the second equation:} \\
5x-2(9-2x)=18 \\
5x-18+4x=18 \\
9x-18=18 \ \ \ |\div 9 \\
x-2=2 \ \ \ |+2 \\
x=4 \\ \\
y=9-2x=9-2 \times 4=9-8=1 \\ \\
\boxed{(x,y)=(4,1)}$

6 0

2 years ago

Read 2 more answers

PLSSS HELP! Can someone pls tell me how to do this. y=1/3(x+2)^2, y=x+3

Leokris [45]

Answer:

There you go.

Step-by-step explanation:

Please do tell me if it's wrong.

7 0

2 years ago