Answer:
Vol of 4 moles CO₂(g) at STP = 89.6 Liters
Explanation:
STP
P = 1 Atm
V =
T = 0°C = 273 K
n = 4 moles
R = 0.08206 L·Atm/mol·K
Using Ideal Gas Law PV = nRT => V = nRT/P
V = (4 moles)(0.08206 L·Atm/mol·K)(273 K)/(1 Atm) = 89.6 Liters
Answer:
41.4 g
Explanation:
2Na(s) + 2H2O (l) ----> 2NaOH ( aq) + H2 (g)
According to the above balnced chemical equation the ratio between moles of H2 gas formed to moles of Na used up is 1:2
Molar mass ( Mass of 1 mol) Of H2 gas is 2 gmol-1
So in 1.8 g of H2 0.9 mol should be present
Therefore no. of moles of Na used should be 2× 0.9 = 1.8 moles
Molar mass of Na= 23 gmol-1
So mass of 1.8 mol of Na = 1.8× 23 g = 41.4g
Answer:
1.) protons or electrons 2.) ion
Explanation:
Answer:5
Explanation:In order to be able to say how many sig figs are used for the measurement 811.40 g, you need to know that
<span><span>
non-zero digits are always significant</span><span>
a trailing zero that follows a decimal point and a non-zero digit is always significant</span></span>
In your case, the measurement
<span>811.40</span>
has four non-zero digits and one significant trailing zero.
<span><span><span>8,1,1,4</span>→</span> non-zero digits<span><span>8,1,1,</span>0→</span> significant trailing zero</span>
Therefore, you can say that this measurement has <span>five significant figures</span>
<span>811.40→</span> <span>five significant figures</span>