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olga_2 [115]
4 years ago
11

If 1.320 moles of CH4 reacts completely with oxygen, how many grams of H2O can be formed

Chemistry
2 answers:
Alex17521 [72]4 years ago
8 0

Answer:

mass H2O = 47.56 g

Explanation:

balanced reation:

  • CH4 + 2O2 → CO2 + 2H2O

∴ moles CH4 = 1.320 mol

⇒ moles H2O = (1.320 mol CH4)×(2 mol H2O/mol CH4)

⇒ moles H2O = 2.64 mol H2O

∴ molar mass (mm) H2O = 18.015 g/mol

⇒ mass H2O = (2.64 mol H2O)×(18.015 g/mol)

⇒ mass H2O = 47.56 g

Rainbow [258]4 years ago
3 0

Answer:

47.5 g of water can be formed

Explanation:

This is the reaction:

CH₄  +  2O₂  →  CO₂ + 2H₂O

Methane combustion.

In this process 1 mol of methane react with 2 moles of oxygen to produce 2 moles of water and 1 mol of carbon dioxide.

As ratio is 1:2, I will produce the double of moles of water, with the moles of methane I have.

1.320 mol  .2 = 2.64 moles

Now, we can convert the moles to mass (mol . molar mass)

2.64 mol . 18g/mol = 47.5 g

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Cohesion, adhesion, and surface tension are characteristics of water that ________. increase when pH increases increase when tem
Ray Of Light [21]

Answer:

are a result of hydrogen bonding.

Explanation:

The <em>surface tension</em><em> is the amount of energy required to stretch or increase the surface of a liquid by a unit area</em>. <u>Liquids that have strong intermolecular forces also have high surface tensions.</u> Thus, because of hydrogen bonding, water has a considerably greater surface tension than most other liquids.

Another example of surface tension is capillary action. A thin film of water adheres to the wall of the glass tube. The surface tension of water causes this film to contract, and as it does, it pulls the water up the tube. Two types of forces bring about capillary action.

One is <em>cohesion</em><em>, which is the intermolecular attraction between like molecules (in this case, the water molecules)</em>. The second force, called <em>adhesion</em><em>, is an attraction between unlike molecules, such as those in water and in the sides of a glass tube</em>. If adhesion is stronger than cohesion, the contents of the tube will be pulled upward. This process continues until the adhesive force is balanced by the weight of the water in the tube.

This <u>characteristics of water are a consequence of a particularly strong type of intermolecular attraction, called the </u><u>hydrogen bond</u><u>, which is a special type of dipole-dipole interaction between the hydrogen atom in a polar bond, such as N-H, O-H, or F-H, and an electronegative O, N, or F atom.</u>

8 0
3 years ago
Find the force of an object that has an acceleration of 6.7 m/s2 and a mass of 12 kg.
ira [324]
It would be 80.4 newtons
6 0
3 years ago
If your end product is 200.0 g KMnO4 how much KOH did you start with?
aniked [119]

Answer:

m_{KOH}= 142.0gKOH

Explanation:

Hello there!

In this case, according to the following chemical reaction we found on goo gle as it was not given:

2MnO_2+4KOH+O_2\rightarrow 2KMnO4+2KOH+H_2

Whereas we can see a 2:4 mole ratio of potassium permanganate product to potassium hydroxide reactant with molar masses of 158.03 g/mol and 54.11 g/mol respectively. In such a way, by developing the following stoichiometric setup, we obtain the mass of KOH to start with:

m_{KOH}=200.0gKMnO_4*\frac{1molKMnO_4}{158.03gKMnO_4}*\frac{4molKOH}{2molKMnO_4}  *\frac{56.11gKOH}{1molKOH}\\\\m_{KOH}= 142.0gKOH

Best regards!

8 0
3 years ago
How much energy is evolved during the reaction of 51.2 g of al, according to the reaction below? assume that there is excess fe2
sesenic [268]

Answer : The amount of energy evolved during the reaction is, -807.696KJ.

Solution : Given,

\Delta H=-852KJ

Mass of Al = 51.2 g

Molar mass of Al = 27 g/mole

First we have to calculate the moles of Al.

\text{ Moles of Al}=\frac{\text{ Mass of Al}}{\text{ Molar mass of Al}}=\frac{51.2g}{27g/mole}=1.896moles

The balanced combustion reaction is,

Fe_2O_3+2Al\rightarrow Al_2O_3+2Fe

From the given reaction, we conclude that

As, 2 moles of Al evolved energy = -852KJ

So, 1.896 moles of Al evolved energy = \frac{-852KJ}{2moles}\times 1.896moles=-807.696KJ

Therefore, the amount of energy evolved during the reaction is, -807.696KJ.

8 0
3 years ago
50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0
creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA =  0.010 ×  50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0
3 years ago
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