Answer:
are a result of hydrogen bonding.
Explanation:
The <em>surface tension</em><em> is the amount of energy required to stretch or increase the surface of a liquid by a unit area</em>. <u>Liquids that have strong intermolecular forces also have high surface tensions.</u> Thus, because of hydrogen bonding, water has a considerably greater surface tension than most other liquids.
Another example of surface tension is capillary action. A thin film of water adheres to the wall of the glass tube. The surface tension of water causes this film to contract, and as it does, it pulls the water up the tube. Two types of forces bring about capillary action.
One is <em>cohesion</em><em>, which is the intermolecular attraction between like molecules (in this case, the water molecules)</em>. The second force, called <em>adhesion</em><em>, is an attraction between unlike molecules, such as those in water and in the sides of a glass tube</em>. If adhesion is stronger than cohesion, the contents of the tube will be pulled upward. This process continues until the adhesive force is balanced by the weight of the water in the tube.
This <u>characteristics of water are a consequence of a particularly strong type of intermolecular attraction, called the </u><u>hydrogen bond</u><u>, which is a special type of dipole-dipole interaction between the hydrogen atom in a polar bond, such as N-H, O-H, or F-H, and an electronegative O, N, or F atom.</u>
Answer:

Explanation:
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In this case, according to the following chemical reaction we found on goo gle as it was not given:

Whereas we can see a 2:4 mole ratio of potassium permanganate product to potassium hydroxide reactant with molar masses of 158.03 g/mol and 54.11 g/mol respectively. In such a way, by developing the following stoichiometric setup, we obtain the mass of KOH to start with:

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Answer : The amount of energy evolved during the reaction is,
.
Solution : Given,

Mass of Al = 51.2 g
Molar mass of Al = 27 g/mole
First we have to calculate the moles of Al.
The balanced combustion reaction is,

From the given reaction, we conclude that
As, 2 moles of Al evolved energy = 
So, 1.896 moles of Al evolved energy = 
Therefore, the amount of energy evolved during the reaction is,
.
25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.
The equation of the reaction is;
NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)
We can use the titration formula;
CAVA/CBVB = NA/NB
CA= concentration of acid
VA = volume of acid
CB = concentration of base
VB = volume of base
NA = number of moles of acid
NB = number of moles of base
CB = 0.010 M
VB = 50.0 ml
CA = 0.50 M
VA = ?
NA = 1
NB = 1
Substituting values;
CAVANB = CBVBNA
VA = 0.010 × 50.0 × 1/ 0.50 × 1
VA = 1 ml
Since the total volume of acid used is 1 ml and each drop contains 0.040 ml
The number of drops required is 1ml/0.040 ml = 25 drops
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