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Softa [21]
2 years ago
10

Choose the correct solution in roster form.

Mathematics
2 answers:
Digiron [165]2 years ago
5 0
The first one is d and the second one is b
Sav [38]2 years ago
4 0

Mathematically speaking, roster form of a set is a list of elements that are in the set.

Basically, to represent a set in roster form, we simply list the elements of the set, separated by commas, within braces.

as per the question, consider the set, S, described verbally:

   S = {all prime numbers less than 15}

To write this in roster form, we would first identify all the elements in the set. Let's see. . . the integers that are strictly greater than 0 and less than or equal to 4 would be the integers that are between 0 and 4, not including 0, but including 4, so 1, 2, 3, and 4.

Now we just write these integers, separated by commas, within braces.

S = {2, 3, 5, 7, 11, 13}. So answer is option A

Set notation is a representation of a set of the form {element | properties of that element}.

To represent the inequality in set builder notation, we will first have to solve for the inequality as follows:

9t - 4 >32

Step 1: Add 4 on LHS(Left hand side) and RHS(right hand side) of the inequality.

9t > 36

Step 2: Divide LHS and RHS by 9

t > 4

This means that the inequality holds for all values of t greater than 4 i.e.

{ t | t > 4 }. so answer is option A


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frez [133]
Where’s the root to the question
4 0
2 years ago
Discuss the validity of the following statement. If the statement is always​ true, explain why. If​ not, give a counterexample.
Zigmanuir [339]

Answer:

P(E \cup F)=P(E)+P(F).

Step-by-step explanation:

Given the statement

If P(E)+P(F)=P(E \cup F)+P(E \cap F), then E and F are mutually exclusive events.

If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.

Therefore, the statement is always true as P(E∩F)=0

For mutually exclusive events:

P(E \cup F)=P(E)+P(F).

3 0
3 years ago
3. There were 567 whos in Whoville. Each who ate 814 bowls of
Rasek [7]
All together, there were 461,538 bowls of stew eaten all together.
6 0
2 years ago
3n+4 first the 7 terms
kiruha [24]

Answer:

4, 7, 10, 13, 16, 19, 22

Step-by-step explanation:

Not sure if there is more to this question but here is what I assume:

We want to find the first 7 terms of this equation given 3n+4

Assuming we are starting at 0 we plug 0 in for n.

3(0) + 4 → 4

So our first answer is 4

We continue by pugging in the next numbers after that to get to the first 7 terms

3(1) + 4 → 7

3(2) + 4 → 10

3(3) + 4 → 13

3(4) + 4 → 16

3(5) + 4 → 19

3(6) + 4 → 22

5 0
3 years ago
Answer:
emmainna [20.7K]

Let the numbers be n, n+2, n+4

Sum equals too= 13+2(n+4), which is 2n+21

a) Equation--> n+n+2+n+4= 2n+21

b) Solution--> 3n+6= 2n+21

                      => n= 15

c) Second number--> 17 (15+2)

   Third number--> 19 (15+4)

d) 15+15+2+15+4=30+21

   => 51= 51

So, the equation is true.

And pls mark me brainliesttt :)))

8 0
2 years ago
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