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sineoko [7]
2 years ago
13

Answer:

Mathematics
1 answer:
emmainna [20.7K]2 years ago
8 0

Let the numbers be n, n+2, n+4

Sum equals too= 13+2(n+4), which is 2n+21

a) Equation--> n+n+2+n+4= 2n+21

b) Solution--> 3n+6= 2n+21

                      => n= 15

c) Second number--> 17 (15+2)

   Third number--> 19 (15+4)

d) 15+15+2+15+4=30+21

   => 51= 51

So, the equation is true.

And pls mark me brainliesttt :)))

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if you double the input of a function and it results in twice the output and if you triple the input and it result in three time
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A function behaving as you state is a linear function, which means that the output varies directly with the input.

So, there exists some constant k \in \mathbb{R} such that your function is in the form

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In fact, if you double the input, you have

f(2x) = k\cdot(2x) = 2\cdot (kx) = 2f(x)

And similarly

f(3x) = k\cdot(3x) = 3\cdot (kx) = 3f(x)

Note that this is a guess, it may happen that output doubles (triples) if you double (triple) the input, and still the function is not like y=kx.

For example, the function

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So, it may seems that doubling and tripling the input doubles and triples the output, but this is not true for every input, for example,

f(2) = 2,\ f(4) = 6

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3 years ago
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