C 12 minutes is the correct answer. Hope this helps :)
Answer:
a. Identify the population of interest in this study.
- all the population of the country
b. Identify the sample for the study.
- 50 adults (the ones that were surveyed)
c. Identify the parameter of interest in the study.
- the parameter of interest is the people that believe that coffee shops are overpriced
d. Find and interpret a 95% confidence interval for the parameter of interest.
z score for a 95% confidence level = 1.96
margin of error (E) = z score x √{[0.4(1 - 0.4)] / 50} = 1.96 x 0.069282 = 0.13579
95% confidence level interval:
0.4 - 0.13579 = 0.26421
0.4 + 0.13579 = 0.53579
- 95% confidence interval (0.26421 , 0.53579)
Answer:
d≈91.63m
Step-by-step explanation:
d=w2+l2=78.92+46.62≈91.63389m
Answer:
C. The chance to be selected into the sample was the same for all veterinarians
Y/x = 9/12 = 3/4
so
y = (3/4)x . . . . . . both x and y in dollars.