Answer:
we divide 192 by the volume 19.5
192÷19.5=9.85 so the necklace is made of bronze
The values of the function when x = 1 are y = 1 and y = 1
<h3>How to choose one value that is in the domain of both y(x) = x^2 and y^2 = x?</h3>
The functions are given as:
y(x) = x^2
y^2 = x
Also, the graphs of the functions are given.
From the given graph, we have:
- The domain of y(x) = x^2 is the set of all real numbers
- The domain of y^2 = x is the set of all real numbers greater than or equal to 0
The common numbers in both domain are represented by x >= 0
An example of such number is
x = 1
So, we have:
y(1) = 1^2 ⇒ y(1) = 1
y^2 = 1 ⇒ y = 1
Hence, the values of the function when x = 1 are y = 1 and y = 1
Read more about domain and range at:
brainly.com/question/2264373
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Find gradient by changing form of equation: y = 2/3x + 4. Gradient is 2/3.
Find y intercept of other line by substituting the coordinates: -8/3
Use information to write out equation of line: y= 2/3x - 8/3
Convert to standard form: -2x + 3y = 8.
Hope this helps :)
Answer:
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Answer:
the answer is B
Step-by-step explanation:
5th root of 32 = 2
5 / 5 = cancels
10 / 5 = 2
15 / 5 = 3
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