The frequency of light from a laser is 4.878 x10^ 14 s-1 hertz
<h3>Steps</h3>
v= c/ lambda
c= 3.00 x10^8 m/s
nm into meters
615nm (1m/ 1x10^9 nm) = 6.15x 10^-7 m
use frequency formula
v = 3.00 x10^8 m/s // 6.15 x10 ^-7
v = 4.878 x10^ 14 s-1 hertz
The frequency of light from a laser is 4.878 x10^ 14 s-1 hertz
<h3>What do you mean by frequency?</h3>
- The quantity of waves that pass a set location in a predetermined period of time is known as frequency.
- Therefore, if a wave passes through in half a second, the frequency is 2 per second.
- The frequency is 100 times per hour if it takes 1/100 of an hour.
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Answer:
Explanation:
Given
coefficient of kinetic friction
mass of locomotive=180,000 kg
v=10 m/s
deceleration provided by friction
Time taken to stop completely is
v=u+at
where v=final velocity
u=initial velocity
a=acceleration
t=510.20 s
Distance traveled during this point
s=2551.02 m
The time it takes the Polonium-194 to decay to 1/16 of its original amount is 2.8 seconds.
<h3>What is half-life?</h3>
half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay
To calculate the time it takes the sample of Polonium-196 to decay to 1/16 of its original amount, we use the formula below
Formula:
- = R/R'......... Equation 1
Where:
- n = Total number of time it takes Polonium-194 to decay to 1/16 of its original amount
- t = Half-life of Polonium-194
- R = Original amount of Polonium-194
- R' = Amount of Polonium-194 after decay
From the question,
Given:
Substitute these values into equation 1 and solve for n
Equating the base,
- n/0.7 = 4
- n = 0.7×4
- n = 2.8 seconds.
Hence, the time it takes the Polonium-194 to decay is 2.8 seconds.
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Copper, gold and silver are three of them.