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2 years ago

WILL GIVE BRAINLIST

Physics

2 answers:

tiny-mole [99]2 years ago

8 0

Answer:

This graph shows how much damage was done by natural disasters.

Explanation:

This graph shows, in billions of dollars, how much destruction was caused by different natural disasters in the United States during 2011. The five types of disasters are Landslide, Earthquake, Wildfire, Hurricane and Tornado. The highest amount of damage was caused by tornados, which totaled over $30 billion in damages. The second largest is hurricanes, which caused about $22 billion. The third is landslides, which was less than $5 billion. The fourth is wildfires, with about $1 billion in damages. Lastly, earthquakes with less than $1 billion in damages. What does this mean? During 2011, in the US, billions of dollars were paid to handle these hazards, with tornados and hurricanes being the number one cause.

marshall27 [118]2 years ago

3 0

Answer:

The Graph Shows World Disasters.

Answer Pt.2:

As we all can see the tornado's Have the highest ratings of natural disasters, Hurricane's happen the next most, Landslide's happen less often, Wildfires also happen less often whereas Earthquakes nearly never happen, they are very rare to the world.

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vaieri [72.5K]

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4 years ago

15. A volleyball player who weighs 650 Newtons jumps 0.500 meters vertically off the floor. What is her kinetic energy just befo

allochka39001 [22]

<h2>Kinetic energy just before hitting the floor is 324.57 J</h2>

Explanation:

Weight of volleyball player = 650 N

That is

Mass x Acceleration due to gravity = 650

Mass x 9.81 = 650

Mass = 66.26 kg

We also have equation of motion v² = u² + 2as

Initial velocity, u = 0 m/s

Acceleration, a = 9.81 m/s²

Final velocity, v = ?

Displacement, s = 0.5 m

Substituting

v² = u² + 2as

v² = 0² + 2 x 9.81 x 0.5

v = 3.13 m/s

Velocity with which he lands on ground is 3.13 m/s

We have kinetic energy = 0.5 x Mass x Velocity²

Substituting

Kinetic energy = 0.5 x 66.26 x 3.13²

Kinetic energy = 324.57 J

Kinetic energy just before hitting the floor is 324.57 J

3 0

3 years ago

A ball is thrown down vertically with an initial speed of 31 ft/s from a height of 40 ft. (a) What is its speed just before it s

ICE Princess25 [194]

Answer:

a. 41.96ft/s

b. 1.096s

Explanation:

a. v²=u²+2gs

v²=31²+2×10×40

V=41.96ft/s

b. t=(v-u) /g

t=(41.96-31)/10

t=1.096s

5 0

3 years ago

A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.90 x 105 P

worty [1.4K]

Answer:

The magnitude of the force is 34.59 N.

Explanation:

Given that,

Inside pressure $P_{in}= 1.90\times10^{5}\ Pa$

Area $A=3.90\times10^{-4}\ m^2$

Outside pressure = 1 atm

We need to calculate the magnitude of the force

Using formula of force

$F_{net}=F_{in}-F_{out}$

$F_{net}=(P_{in}-P_{out})A$

Where, $P_{in}$ =inside Pressure

$P_{out}$ =outside Pressure

A = area

Put the value into the formula

$F_{net}=(1.90\times10^{5}-1.013\times10^{5})3.90\times10^{-4}$

$F_{net}=34.59\ N$

Hence, The magnitude of the force is 34.59 N.

6 0

3 years ago

Consider a 20 cm thick granite wall with a thermal conductivity of 2.79 W/m·K. The temperature of the left surface is held const

kozerog [31]

Answer:

The right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²

Explanation:

Thickness of the wall is L= 20cm = 0.2m

Thermal conductivity of the wall is K = 2.79 W/m·K

Temperature at the left side surface is T₁ = 50°C

Temperature of the air is T = 22°C

Convection heat transfer coefficient is h = 15 W/m2·K

Heat conduction process through wall is equal to the heat convection process so

$Q_{conduction} = Q_{convection}$

Expression for the heat conduction process is

$Q_{conduction} = \frac{K(T_1 - T)}{L}$

Expression for the heat convection process is

$Q_{convection} = h(T_2 - T)$

Substitute the expressions of conduction and convection in equation above

$Q_{conduction} = Q_{convection}$

$\frac{K(T_1 - T_2)}{L} = h(T_2 - T)$

Substitute the values in above equation

$\frac{2.79(50- T_2)}{0.2} = 15(T_2 - 22)\\\\T_2 = 35.5^\circC$

Now heat flux through the wall can be calculated as

$q_{flux} = Q_{conduction} \\\\q_{flux} = \frac{K(T_1 - T_2)}{L}\\\\q_{flux} = \frac{2.79(50 - 35.5)}{0.2}\\\\q_{flux} = 202.3W/m^2$

Thus, the right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²

6 0

3 years ago

WILL GIVE BRAINLIST ​

WILL GIVE BRAINLIST