Answer:
![p(s) = -24s^2 +2200 s -18000](https://tex.z-dn.net/?f=%20p%28s%29%20%3D%20-24s%5E2%20%2B2200%20s%20-18000)
If we use the valie of s =60 we have
![p(60) = -24 (60)^2 +2200*60 -18000](https://tex.z-dn.net/?f=%20p%2860%29%20%3D%20-24%20%2860%29%5E2%20%2B2200%2A60%20-18000)
And after solve we got:
![p(60)= -86400 +132000 -18000 =27600](https://tex.z-dn.net/?f=%20p%2860%29%3D%20-86400%20%2B132000%20-18000%20%3D27600)
So then the best option for this case would be:
$27,600
Step-by-step explanation:
Using the following info in order to complete the problem:
p(s)=-24s^(2)+2200s-18000
$112,560
$27,600
$111,120
$236,400
$14,240
We have the following function given:
![p(s) = -24s^2 +2200 s -18000](https://tex.z-dn.net/?f=%20p%28s%29%20%3D%20-24s%5E2%20%2B2200%20s%20-18000)
If we use the valie of s =60 we have
![p(60) = -24 (60)^2 +2200*60 -18000](https://tex.z-dn.net/?f=%20p%2860%29%20%3D%20-24%20%2860%29%5E2%20%2B2200%2A60%20-18000)
And after solve we got:
![p(60)= -86400 +132000 -18000 =27600](https://tex.z-dn.net/?f=%20p%2860%29%3D%20-86400%20%2B132000%20-18000%20%3D27600)
So then the best option for this case would be:
$27,600
Answer:
3t + 81
Step-by-step explanation:
1. First, let's simplify 7t+6w−4t+2w
2. As you can see, the first choice matches with our solution.
Therefore, 3t + 81 is equivalent to 7t+6w-4t+2w.
-4x + 2x = -2x
6 + 5 = 11
Therefore, 11 - 2x = 0
11 = 2x
x = 11/2 = 5.5
Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24