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Sergeeva-Olga [200]
3 years ago
15

Consider the reaction: 2NO(g) + 2H2(g) → N2(g) + 2H2O(g) A suggested mechanism for this reaction follows: (1) NO(g) + NO(g) → N2

O4(g) (slow) (2) N2O4(g) + H2(g) → N2(g) + H2O2 (g) (fast) (3) H2O2(g) + H2(g) → 2H2O(g) (fast) Based on this mechanism, which, if any, of the following actions will not affect the rate of the reaction?
Chemistry
1 answer:
Dominik [7]3 years ago
4 0

Hello. This question is incomplete. The full question is:

"Consider the following reaction.  2NO(g) + 2H2(g) → N2(g) + 2H2O(g)

A proposed reaction mechanism is:  NO(g) + NO(g) N2O2(g) fast  N2O2(g) + H2(g) → N2O(g) + H2O(g) slow  N2O(g) + H2(g) → N2(g) + H2O(g) fast

What is the rate expression?  A. rate = k[H2] [NO]2  B. rate = k[N2O2] [H2]  C. rate = k[NO]2 [H2]2  D. rate = k[NO]2 [N2O2]2 [H2]"

Answer:

A. rate = k[H2] [NO]2

Explanation:

A reaction mechanism is a term used to describe a set of phases that make up a chemical reaction. In these phases a detailed sequence of each step is shown, composed of several complementary reactions, which occur during a chemical reaction.

These mechanisms are directly related to chemical kinetics and allow changes in reaction rates to be observed in advance.

Reaction rate, on the other hand, refers to the speed at which chemical reactions occur.

Based on this, we can observe through the reaction mechanism shown in the question above, that the action "k [H2] [NO] 2" would have no changes in the reaction rate.

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stira [4]
1)

<span>m(NaCl) = 1.95 g
V(H2O) = 250mL
M(NaCl) = </span><span>58.5 g/mole

Since waters density value is 1g/mL, it can be assumed that volume and mass of water are same values:

</span>V(H2O) = 250ml = 250g = 0.25 kg<span>

</span><span>molality of NaCl:
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n(NaCl)=m/M=1.95/58.5= 0.033 mole

</span>molality b(NaCl)=n(NaCl) / V (H2O)= 0.033/0.25 = 0.132 mol/kg
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milimolality of NaOH = 0.132/0,001 = 132 mmole/kg
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milliosmolality of NaOH = milimolality x N of ions formed in dissociation

Since NaCl dissociates into 2 ions in solution:
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m(gl) = 9 g
V(H2O) = 250mL
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Since waters density value is 1g/mL, it can be assumed that volume and mass of water are same values:

V(H2O) = 250ml = 250g = 0.25 kg

molality of glucose:

n(gl)=m/M=9/180= 0.05 mole

molality b(gl)=n(gl) / V (H2O)= 0.05/0.25 = 0.2 mol/kg

milimolality of glucose = 0.132/0,001 = 200 mmole/kg

milliosmolality of glucose = milimolality x N of ions formed in dissociation

Since glucose does not dissociate, milimolality and milliosmolality are same:
                                        
milliosmolality of glucose = 200 osmoles/kg

3)

The osmosis represents the diffusion of solvent molecules through a semi-permeable membrane that allows passage solvent molecules but does not to the dissolved substance molecule. The osmosis occurs when the concentrations of the solution on both sides of the membrane are different. Since the semi-permeable membrane only permeates the solvent molecules, but not the particles of the dissolved substance, it occurs the solvent diffusion through the membrane, i.e. the solvent molecules pass through the membrane to equalize the concentration on both sides of the membrane. Solvents molecules move from the middle with a lower concentration in the middle with a higher concentration of dissolved substances.

In our case, osmosis will occur because the concentration of NaCl solution and the concentration of glucose solution do not have same values. Osmosis will occur in the direction of glucose solution because it has a lower concentration.

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