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WITCHER [35]
3 years ago
11

How many hydrogen atoms are found in 3H2CO3?

Chemistry
1 answer:
Fiesta28 [93]3 years ago
5 0

Answer:

6

Explanation:

The number of hydrogen atoms in the given compound is 6 atoms.

  Given compound is:

              3H₂CO₃

An atom is the smallest indivisible particles of an element.

  In the compound;

             3H₂CO₃

          Elements          Number of atoms

               H                       3(2)  = 6

               C                       3(1)   = 3

               O                       3(3)    = 9

The number of hydrogen atoms in the compound is 6

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Laura jala un trineo una distancia de 2000 cm usando una cuerda, con una tensión constante de 80 N. La tarea requiere de 800 J d
Andre45 [30]

Respuesta:

60°

Explicación:

Paso 1: Información dada

  • Distancia recorrida (d): 2000 cm
  • Fuerza aplicada (F): 80 N
  • Trabajo realizado (W): 800 J

Paso 2: Convertir "d" a metros

Usaremos el factor de conversión 1 m = 100 cm.

2000 cm × 1 m/100 cm = 20 m

Paso 3: Calcular el ángulo entre la cuerda y el suelo (θ)

W = F × d × cosθ

800 J = 80 N × 20 m × cosθ

θ = 60°

5 0
3 years ago
The ksp for silver sulfate (ag2so4) is 1. 2 ✕ 10-5. Calculate the solubility of silver sulfate in each of the following
Allisa [31]

For ksp of silver sulfate (ag2so4) at 1. 2 ✕ 10-5, the solubility of silver sulfate is mathematically given as

x = 5.26*10^{-4}

<h3>What is the solubility of silver sulfate in 0.15 M AgNO3?</h3>

Generally, the equation for the  Chemical reaction is mathematically given as

Ag2SO4 ⇄ 2Ag+  + SO4 2-

Therefore

Ksp = [Ag+ ]2 *[SO4 2-]

1.2*10-5 = ( 0.15 +2x)2*(x)

x = 5.26*10^{-4}

In conclusion, the solubility of silver sulfate is

x = 5.26*10^{-4}

Read more about Chemical reaction

brainly.com/question/16416932

8 0
2 years ago
Read 2 more answers
2LiClO+KHSO - Li2SO4 + Cl2 + KOOH
agasfer [191]

Answer:

2.5 moles of KOOH are produced.

Explanation:

1)Given data:

Number of moles of KOOH produced = ?

Number of moles of LiClO = 5 mol

Solution:

Chemical equation:

2LiClO +  KHSO₄     →      Li₂SO₄ + Cl₂ + KOOH

now we will compare the moles of KOOH and LiClO.

                 LiClO          :          KOOH

                    2              :              1

                   5               :             1/2×5 = 2.5

2.5 moles of KOOH are produced.

4 0
3 years ago
Una piedra es lanzada horizontalmente desde la azote de un edificio de 30 metros de altura, con una velocidad de 12 m/s. Hallar
drek231 [11]

Answer: La piedra tarda 2.47 segundos en caer al suelo, y cae a 29.64 metros de la base del edificio.

Explanation:

Ok, tenemos 2 sistemas de ecuaciones para este problema.

Primero, el vertical:

La aceleración es la aceleración gravitatoria, entonces:

a = -9.8m/s^2

para la velocidad podemos integrar sobre el tiempo y obtenemos

v = (-9.8m/s^2)*t + v0

donde v0 es la velocidad inicial, pero la velocidad inicial es solo horizontal, entonces v0 = 0.

Para la posición integramos de vuelta:

p = (1/2)*(-9.8m/s^2)*t^2 + p0

donde p0 es la posición inicial, en este caso, 30m

p = (-4.9m/s^2)*t^2 + 30m

la piedra va a llegar al piso cuando la posición vertical sea igual a 0m

p = 0m =  (-4.9m/s^2)*t^2 + 30m

de aca podemos despejar el tiempo que la piedra tarda en llegar al suelo.

t = √(30/4.9) segundos = 2.47 s.

Ahora, las ecuaciones para el movimiento horizontal son:

Aceleración nula, pues no hay ninguna fuerza actuando en la dirección horizontal.

a = 0

para la velocidad, integramos sobre el tiempo:

v = 0*t + v0 = v0

donde v0 es la velocidad inicial, en este caso, es 12m/s

v = 12m/s

para la posición integramos de vuelta:

p = 12m/s*t + p0

en este caso podemos asumir que estamos inicialmente en el punto x = x0, asi que la posición inicial es p0 = x0.

p = 12m/s*t + x0

entonces, si queremos calcular la distancia entre la base del edificio y el punto donde cae la piedra, tenemos que calcular:

D = p(2.47s) - p(0s)

D = 12m/s*2.47s + x0 - (12m/s*0s + x0)

D = 29.64m

La piedra tarda 2.47 segundos en caer al suelo, y cae a 29.64 metros de la base del edificio.

3 0
3 years ago
58.0 g of K2SO4 was dissolved in 500 g of water. What is the molality of this solution?
podryga [215]

Answer: The molality of solution is 0.66 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n\times 1000}{W_s}

where,

n = moles of solute

W_s = weight of solvent in g

moles of K_2SO_4 = \frac{\text {given mass}}{\text {Molar Mass}}=\frac{58.0g}{174g/mol}=0.33mol

Now put all the given values in the formula of molality, we get

Molality=\frac{0.33\times 1000}{500g}=0.66mole/kg

Therefore, the molality of solution is 0.66 mole/kg

7 0
3 years ago
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