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Tamiku [17]
3 years ago
9

What physical properties affect an object’s gravitational pull?

Chemistry
1 answer:
Leto [7]3 years ago
5 0

Answer:

D) All of the above

Explanation:

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HELPPPPPPP<br><br>DETERMINE THE CHARGE OF ELECTRON CLOUD OF POTASSIUM ​
tensa zangetsu [6.8K]

Answer:

+1

Explanation:

A Potassium atom is represented with the sign "K" in chemistry and have atomic number 19.

The charge of electrons causes a matter to experience a force and it can be positive or negative.

In Potassium atom, the electric charge is +1 to enter a stable electron configuration as there is only one valence electron in the outermost shell of potassium atom. As potassium atom will lose electron it will become positively charged.

Hence, the correct answer is "+1".

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Medications for skin , and medication for babies
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I NEED APPROPRIATE ANSWERS SO IF ANYONE CAN PLEASE ANSWER THESE TWO QUESTIONS I WILL GIVE YOU BRAINIEST. Can someone please help
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Answer:

1. When salt is mixed with water, the salt dissolves because the covalent bonds of water are stronger than the ionic bonds in the salt molecules

2. Pure sodium explodes on contact with water

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What does the chemical formula cacl2 show about the compound it represents? The person who answered this question first was wron
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In a crystal of calcium chloride the chlorine atoms is two times more than calcium atoms.
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Calculate ΔG o for the following reaction at 25°C: 3Mg(s) + 2Al3+(aq) ⇌ 3Mg2+(aq) + 2Al(s) Enter your answer in scientific notat
larisa [96]

Answer:

-3.7771 × 10² kJ/mol

Explanation:

Let's consider the following equation.

3 Mg(s) + 2 Al³⁺(aq) ⇌ 3 Mg²⁺(aq) + 2 Al(s)

We can calculate the standard Gibbs free energy (ΔG°) using the following expression.

ΔG° = ∑np . ΔG°f(p) - ∑nr . ΔG°f(r)

where,

n: moles

ΔG°f(): standard Gibbs free energy of formation

p: products

r: reactants

ΔG° = 3 mol × ΔG°f(Mg²⁺(aq)) + 2 mol × ΔG°f(Al(s)) - 3 mol × ΔG°f(Mg(s)) - 2 mol × ΔG°f(Al³⁺(aq))

ΔG° = 3 mol × (-456.35 kJ/mol) + 2 mol × 0 kJ/mol - 3 mol × 0 kJ/mol - 2 mol × (-495.67 kJ/mol)

ΔG° = -377.71 kJ = -3.7771 × 10² kJ

This is the standard Gibbs free energy per mole of reaction.

5 0
3 years ago
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