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mel-nik [20]
3 years ago
15

The number of atom of each element present in 2 formula Fe(No3)2​

Chemistry
1 answer:
Lerok [7]3 years ago
4 0

Answer:

Number of Atoms in -

  1. Fe - 1
  2. N - 2
  3. O - 6

Hope it helps?

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Complete the electron-dot structure of s-allylcysteine, showing all lone-pair electrons.
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The structural formula of <span>s-allylcysteine is shown in the picture (top figure). To create its Lewis structure, draw all its bonds between elements. Each single bond contains two electrons. There is an octet rule that must be obeyed by most elements. Each element should be surrounded with 8 electrons. The hydrogen is exempted of this rule. So, there are 4 lone pairs for the S atom, 1 lone pair for the N atom, and 2 lone pairs each for the 2 O atoms.</span>

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Which is a component of John Dalton’s atomic theory?
Dmitry [639]
Atoms of different elements can be identical
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2 years ago
What is the best name for the molecule below? (2 points)
Levart [38]
Given:

A compound with:

Number of carbon atoms = 9
Number of double bonds = 1 
A double bond between 5th and 6th carbon
A propyl group (CH2CH2CH3) branching off the 3rd carbon from the left

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4-propyl-1-hexene

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4 0
3 years ago
Read 2 more answers
An observation balloon was filled with 0.50 atmospheres of Helium, 54.0 mm Hg of Nitrogen, and 0.400 atmospheres of Hydrogen. Wh
noname [10]

Answer:

the pressure would be 0.9 atmospheres

Explanation:

you just gotta add the presures for each of the gases that are added

7 0
3 years ago
A fat is composed of long chains of carbon and hydrogen atoms. In a reaction with a strong base, a fat forms a soap and glycerol
Nonamiya [84]

Answer:

Empirical formula is C₉H₁₅O

Molecular formula = C₈₁H₁₃₅O ₉

Explanation:

Percentage of carbon = 77.60%

Percentage of oxygen = 11.45%

Percentage of hydrogen = 10.95%

Molecular weight = 1253 g/mol

Molecular formula = ?

Empirical formula = ?

Solution:

Number of gram atoms of C = 77.60 g /12g/mol =6.5

Number of gram atoms of O = 11.45 g / 16 g/mol = 0.72

Number of gram atoms of H = 10.95 g / 1.008 g/mol= 10.9

Atomic ratio:

C               :            H                 :    O

6.5/0.72   :       10.9/0.72         :   0.72/0.72

     9          :            15              :         1

C : H : O = 9 : 15 : 1

Empirical formula is C₉H₁₅O

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 1253 / 139

n = 9

Molecular formula = n (empirical formula)

Molecular formula = 9 (C₉H₁₅O )

Molecular formula = C₈₁H₁₃₅O ₉

4 0
3 years ago
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