B. The chemical reaction that represents oxidation - reduction reaction is CaCO3(s) → CaO(s) + CO2(g).
<h3>
Oxidation reduction reaction</h3>
In oxidation reduction reaction, the oxidizing agent is reduced while reducing agent is oxidized.
<h3>In the chemical equation below;</h3>
CaCO3(s) → CaO(s) + CO2(g)
Calcium (ca) is oxidized calcium (II) ion while the carbon (IV) oxide is reduced carbon (IV) oxide.
Thus, the chemical reaction that represents oxidation - reduction reaction is CaCO3(s) → CaO(s) + CO2(g).
Learn more about oxidation reduction reaction here: brainly.com/question/4222605
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The answer is 2.0 moles.
From their coefficients in the balanced chemical equation below for the reaction of tin dioxide with hydrogen gas to produce tin and water:
SnO2(s) + 2H2(g) ==>Sn(l) + 2H2O(g)
two moles of hydrogen gas is to produce one mole of tin. We use this mole ratio to compute for the number of moles of tin as:
moles of Sn = 4.0mol H2 (1mol Sn/2mol H2) = 2.0 mol
Explanation:
The initial concentrations for a mixture :
Acetic acid at equilibrium = 0.15 M
Ethanol at equilibrium = 0.15 M
Ethyl acetate at equilibrium = 0.40 M
Water at equilibrium = 0.40 M
Initially:
0.15 M 0.15 M 0.40 M 0.40 M
At equilibrium
(0.15-x)M (0.15-x) M (0.40+x) M (0.40+x) M
The equilibrium constant is given by expression
![K_c=\frac{[CH_3CO_2C_2H_5][H_2O]}{[CH_3COOH][C_2H_5OH]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3CO_2C_2H_5%5D%5BH_2O%5D%7D%7B%5BCH_3COOH%5D%5BC_2H_5OH%5D%7D)
Solving for x:
x = 0.0333
The equilibrium concentrations for a mixture :
Acetic acid at equilibrium = (0.15-x)M = (0.15-0.033) M = 0.117 M
Ethanol at equilibrium = (0.15-x)M = (0.15-0.033) M = 0.117 M
Ethyl acetate at equilibrium = (0.40+x)M = (0.40+0.033) M = 0.433 M
Water at equilibrium = (0.40+x)M = (0.40+0.033) M = 0.433 M
Answer:
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Answer:
Explanation:
so we have to solve it or just answer it?
