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Salsk061 [2.6K]
3 years ago
6

a circular fountain has a radius of 9.4 feet. find its diameter and circumference to the nearest tenth.

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0

Radius = r

Diameter : D = r*2

Circumference : C = 2πr

π = 3.14 rounded

9.4*2 =18.8

2(3.14)9.4

6.28*9.4= 59.03200

Diameter = 18.8

Circumference = 59.03200


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Romashka-Z-Leto [24]
1. Divide by 4
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2. Square both sides to remove square root
2x+8 = 36

3. Subtract 8
2x = 28

4. Divide by 2 to make x by itself
x = 14
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3 years ago
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If 6m by 15m is a pond ,is 40m would be enough for fencing the pond
Veseljchak [2.6K]
If the pond were a rectangle, then:
length=15 m
width=6 m

We would have to calculate the perimeter of this rectangle.
Perimeter of a rectangle=2(length)+2(width)

Perimeter of this rectangle=2(15 m)+2(6 m)=30 m+12 m=42 m

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3 years ago
If -3m + 1 > 7, which of the following is a solution set for m?
Papessa [141]

ANSWER

m < -2

EXPLANATION

We want to find the solution set for m in:

-3m+1>7

First, collect like terms:

\begin{gathered} -3m>7-1 \\ -3m>6 \end{gathered}

Now, divide both sides by -3. When you divide an inequality by a negative number, <em>the sign changes direction</em>:

\begin{gathered} \frac{-3m}{-3}>\frac{6}{-3} \\ m

This means that all values of m must be less than -2.

<em>None of the options contains the correct solution set.</em>

4 0
1 year ago
Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2

<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

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3 years ago
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Nitella [24]

Answer:

Right angles is 90° so 90°+30°=120°.A straight line is 180°. So you do 180°-120° which is 60. So A=60°

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