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Lisa [10]
3 years ago
11

What is the explicit form of 30,60,90,120,150,180

Mathematics
2 answers:
bezimeni [28]3 years ago
4 0

Let common difference be D

  • <em>d=30</em>

Let the first term be [tex]a_1[/tex]

  • a_1=<em>3</em><em>0</em>

<h3>⚘Formula to find explicit form is:</h3>

\begin{gathered}\\ \sf\longmapsto a_n=a_1+(n-1)d\end{gathered}

  • Putting values__!

\begin{gathered}\\ \sf\longmapsto a_n=30+(n-1)30\end{gathered}

<em>Hence, </em><em>a_{n} = 30 + (n - 1)30</em><em> </em><em>i</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>e</em><em>x</em><em>p</em><em>l</em><em>i</em><em>c</em><em>i</em><em>t</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em> </em><em>o</em><em>f</em><em> </em><em>3</em><em>0</em><em>,</em><em>6</em><em>0</em><em>,</em><em>9</em><em>0</em><em>,</em><em>1</em><em>2</em><em>0</em><em>,</em><em>1</em><em>5</em><em>0</em><em>,</em><em>1</em><em>8</em><em>0</em><em>.</em><em>.</em><em>.</em>

mina [271]3 years ago
3 0

Answer:

<em>Let common difference be D</em>

d = 30

<em>Let the first term be </em>

a_1 = 30

<em>Formula to find </em>the explicit form is:

the explicit form is: a_n = a1 + (n−1)d

Putting values

==> a_n = 30 + (n − 1)30

Hence, a_n = 30 + (n - 1)30 is the explicit form of 30,60,90,120,150,180...

Step-by-step explanation:

Step-by-step explanation:Answer by XxBrainlyUserxX

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<h2>See the explanation.</h2>

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(b)

If we denote the books in stock at the starting of January by B, then

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